** **** **Measures of *land* are quantities of *length *and *surface*. Any surface measure is predicated on the chosen measure of *length*; just as the *volume* measure is a resultant of any given system’s unit of *length*. The land measurement system revealed thus far is based on the “foot”, its subdivisions, and multiples.

But, with the advent of the French Revolution in the 1790’s came an entirely new system of weights and measures. I believe its true intent was to usurp and obliterate from memory the very measures still in use today throughout America; measures which our European ancestors, for reasons long lost even to them, regarded as “sacred”. This “new” system of measurement is based on a *length* measure known as the “meter”; and the system itself they called “metric”.

Amidst one of the bloodiest revolutions the world has ever seen, the French allege they commissioned a scientific survey to measure the distance from the North Pole to the equator, passing through Paris. This measurement was divided into 10,000,000 parts; one of these parts is a “meter”.

It is my contention that the French *never made that, or any other measurement* resulting in the *meter*. That it was, in fact, just another “story” told to “the people”. And what was the motive? Same as for the stories “they” concocted *to conceal from humanity the true origins of their* *ounces*, *gallons*, *inches*, *acres*, and all increments thereof. That story was, and is *still to this day*, for the expressed purpose of continuing to conceal* the greatest hoax ever perpetrated upon humanity*! “Metric” is not only part of the hoax, it is part of the scheme to

*cover-up*the greater hoax

*regarding*. Keep an open mind, and have a look at the evidence that compels me to reach this conclusion.

__all__of our measures The system of measures *named* “metric” is based on a unit of length *named* the “meter”. And the older, *other* system is based on the *length* measure *named* the “foot”. __Both of these systems are inseparable foundational measures structuring the mathematics and geometry of “form”.__ This

*knowledge*is in direct conflict with the “historical record”, and it has been concealed from the public for over two hundred years. Here is just

*some*of the evidence supporting these accusations:

The equation below reads: **2.0** “units” are to **1.0*** millimeter*, as **2.0** “units” *minus* .**4125** “unit” is to **1.0*** inchmeasure*. “Inchmeasure” is my terminology for what otherwise is known as (1/32)”. The *inchmeasure* (**im**) is to the *customary* system as the *millimeter* (**mm**) is to the *metric* system.

**2.0 units **∕** 1.0 mm = (2.0 units ****− .4125 unit) ** ∕** 1.0 im**

** ** Believe it or not, the simple equation above, which is wholly predicated on a “mysterious” **.4125 unit**, * perfectly* resolves the conversion between the lengths of present humanities’ two fundamental units of measurement. Let’s set up the equation and perform a simple “cross-multiplication”. Insert (1/32)” for (im). Then see for yourself that this is

*indeed*absolutely true!

2 / 1.0 mm _{=} (2 − .**4125**) / 1.0 im

2.0(im) = (2 − .**4125**) mm

2.0(1/32)” = (1.5875) mm

__1/16 inch = 1.5875 millimeters __

(and to check the results:)

1.5875 *mm* / 25.4 *mm*/*inch* = .0625 *inch* = 1/16 *inch*

The conversion factor of *exactly ***25.4*** millimeters per inch*, resolving the commensuration between the two systems of length measurement, began to be adopted by various countries in the early 1930s. The *decision* to “round-off” the many different nation’s various versions of 25.399??… to an even **25.4** *millimeters* was an *agreement* by “acclamation”, *and not the conclusion of any new mathematical discovery*. The U.S. and British finally legislated their compliance to this standard in 1959. It remains the conversion factor for all nations to this day. Let’s look at *what* they actually agreed to, regardless of the process by which it was determined.

In metric, the fundamental unit is the *meter *and it subdivides into **1000** *millimeter*s (or *metric measures* “**mm**”, as I like to call them). The *customary* system, in use before *metric*, is based on the *“foot”* (which subdivides into **12** whole *inches*, and multiplies by **3** into *yards*). The *inch* further subdivides into **32** *inch measures* (**im**). Thus, given a fixed unit of length (in this case, **1.0** *inch*), one system divides it into **32** parts (each .03125”), and the other system divides * the same length* into

**25.4**parts (each .03937007874”). Look at the equations below:

**25.4 ***mm* **∕ 32 ***im*** = 0.79375 ***mm* **∕ 1.0 ***im*

and

(**2.0 ***units* **− **.**4125 ***unit*) ∕** 2.0 ***units*** = 0.79375 ****∕ 1.0**

** ** This means that (**2.0 units ****−** .**4125 unit**) is *exactly* equal to 1/32^{nd} *inch* __if the length of 2.0 units exactly equals 1.0 millimeter__.

Or, look at it this way: The difference between (.03937007874*exact*)**”** and (.03125)**”** is (.00812007874*exact*)**”.** This difference, (.00812007874*exact*)**”** *in inches*, is equal to (.**4125 ***exact* ∕ 2) *in millimeters* showing that the equations above and below __perfectly__ reconcile these two systems:

(1.0) *mm* ─ (.**4125***exact* ∕ 2) *mm* = **1.0 ***im*

** ^{ }**Below,

*the same line*is divided into

**254**units on top (mm), and underneath into

**320**units (im).

**|**^{_______________________254________________________}|

^{_______________________254________________________}|

** 320**

** **We can see the same quantities at work *even in the* *difference in the number of increments* between the two systems, i.e. **66** (**320**^{ths}) when expressed as a portion or ratio of the whole line:

66/320 = .20625 = .**4125***exact* ∕ 2

Further investigation shows that **127** *difference measures* equal **1.03125**”; or, (**33**/**32**)”. And of course, **128** equal **1.0393700**…”, which is **1.0**” plus **1.0** mm. And who could have predicted that **480** *units* or *increments* of a **[127 X 128]** quantity of *difference measures* would add up to *exactly* **1.0** *mile*?

**480** X **127** X **128** X .**008120078**…” = **63**,**360**” = **1.0 **mile

The quantity **[127 X 128]** is written that way because it reflects a geometric pattern or arrangement familiar to that already seen in some of the previously exposed geometries defining measures of *weight* and *volume*. In this case, this quantity is modeled by a square grid having **127** units/side with *one additional course* of **127** units added to one edge. This quantity is modeled below along with several others that were exposed in earlier chapters.

Note; The **480** multiplier is a quantity analogous to the **480** *grains* in **1.0** ounce *troy* and the **480** *chains* delineating the edge-length of a t*own*ship grid.

So, as it has been easily demonstrated by the simple previous mathematics, that *only* a (now very *familiar* to readers of previous chapters) **.4125** *quantity* distinguishes modern humanities two systems of measurement.

In fact, the system of *weight measures* described in an earlier chapter and based on the *27 milligram cubet* was also shown to have the same organic mathematical constant:

**.4125 / .99 = .4166666 . . . / 1.0**

This equation incorporates the illuminati’s quantitative constant based on **99** (a land and volume constant) and exposes the *grain/gram* ratio at the heart of the 27 milligram system. It replicates the geometry where in *one 27 milligram* “cubet” there is comparably 0.**4166666** . . . *grain* per **1.0** cube. Since there are 15.43235835 grains/gram:

.027 gram X 15.43235835 grains/gram = 0.**41667**3676 grains

Both systems of weight standards, in their entirety, can now be constructed from this simple **27** mg. cube.

There is another *cube* that is very revealing, as it provides more unequivocal evidence showing the direct geometric connection between *America**’s gold and silver coinage weights* and *both* systems based on the *gram* and the *grain*. Let’s start with “quanta-** sizing**” this cube by having its’

*surface*

*area*measuring

**1543.2**35… square

*units*(which is clearly a

**10**

^{2}powering of

**15.432**35…, or the number of

*grains*in

**1.0**

*gram*)

*.*The edge-length of this cube is

**16.037**64… and its’ volume is

**4124.9**77… cubic units. Wow! What a coincidence.

By starting with the number of grains in one gram (times **10**^{2}) as the cube’s surface area, its’ volume becomes the number of grains in **10** American silver dollar coins: **4125** to be exact. And its’ 16.03764… *edge-length* (*as* *grams*) is the *weight* of the *pure* *gold* content in America’s **10** *dollar* gold coin , the *eagle.* In the 1792 Coinage Act, it was expressed as **247.5** *grains*, which is interesting, since **247.5** as a cube’s *surface* makes each of its’ 6 *faces* **41.25** *square* units. And remember, in 1792 the French were *supposedly* still trying to determine what a *meter* was, let alone *know* the weight of a *gram* *to the tolerance of this 21 ^{st} century*!

If the cube is re-sized so that the surface area is the number of *grains* in just **1.0** *gram*, Then its’ volume becomes **4.125. **The next power of this cube is eight of them together as one cube. This cube’s *volume* is **33** units. So now we know that a cube with a volume of **33** units leads directly to eight geometric sub-units with each having *surface* *areas* measuring **15.432**35… square *units.* But there is something else about a cube this size that indicates even Nature favors this *quanta-size-ation*.

“A cube of *pure* *silver* with a volume of **4.125** cubic *feet* weighs **2700** *pounds*; or, **39375** *troy* *ounces*.” This statement is “true” (only) to the tolerance that **4.12**2969… cubic *feet* approaches the *ideal* **4.125**:

**4.12**2969… / **4.125 **= .**999**50…

which is, as we can see, at least as fine as the .**999** fine *pure* *silver* in today’s **1.0** ounce (troy) U.S. Mint *Silver American Eagle* coins. So imbedded in Nature, cast in pure silver (so to speak), is the *metric* *system* manifesting here as *both* the number of *troy* *ounces* (**39.37**007874” in **1.0** *meter*) and the *surface* *area* (**15.432**35…) of the cube. The **2700** *pounds* mirrors the system of **27** mg. cubets, which is the base unit of *both* systems of *grains* and *grams*. This leads us full circle, right back to the original 1792 gold *eagle* coin and its mandated **270** *grain* gross weight. Remember, a weight of **1.0** *gram* is the equal of **15.43235835**… *grains*:

**1.0** *gram* / **15.43235835**… *grains *= .0**64798**91… / **1.0**

** ** The equation above can be interpreted as saying that: “the relationship between a *grain* and a *gram* is the same as that between a quantity of **648 **and **10,000”**. In the *illuminati’s* system of weight measures based on the **27** mg. cubets, **648** cubets (in perfect geometric arrangements) has the weight of **270** grains, the *eagle’s* gross weight.

None of this is “coincidence” . . . and shortly, we will return to the *gram* and *grain*. But first we should continue exploring the geometric roots of the *lineal* or *length* components of the *meter measure* (**mm**) and the *inch* *measure* (**im**).

In the previous chapter on the *Measures of Land*, we saw what happens when *geometry* divides the *volume* of **1.0** *surface* unit in the form sphere into two new spheres. Remember, the volume of this sphere is .**0940**3159… so the volume of each new sphere (made from the original’s volume) is .**0470**15799… In this sphere’s *transformation by division*, one-half of the original sphere’s *surface* *area* (0.**5**000…) is likewise imparted to each new sphere. But we saw that this is not enough. A sphere with a .**0470**15799… volume has a .**6299**60526…surface area. Thus *each* of the two new spheres is *missing* a .**1299**60526 portion of **1.0** unit of surface. We saw that *this specific quantity* of missing surface area is a *geometric constant* because regardless of *whatever shape or form* that the **1.0** *surface unit* assumes, if it divides its *volume* into two new forms, *identical* to the original form, *each* will be in need of an additional .**1299**60526… surface unit. The *total* *amount* of surface area required to cover the two ½ -volume-unit spheres after the transformation is **1.259921050**… units.

Let’s look at the relationship between these two generations of spheres. We began with a sphere *defined* as having a **1.0** unit *surface* *area*. When it divides its *volume* into two new spheres, there is now **1.259921050**… *surface* units in existence. As you look at the following *mathematical* relationship between these two areas, *understand* that this was a partnership encoded in the very DNA of our cosmos *long before the beginning of time itself***:**

**1.0 ****∕ ** **1.259921050**… = **. 7937**0052…

**∕ 1.0**

**and as was just previously demonstrated**

**25.4 mm ****∕ 32 im = . 7937**5

**∕ 1.0**

** **Even more simply stated:

**(1.0 mm = 1.0” / 25.4) = 1.259921050**…** / 32 **

** ** Now look at what the relationship is between the *lineal* components of the two generations of spheres by comparing their diameters. A sphere equal to **1.0** *surface* unit has a .564189584… diameter; the second generation sphere’s diameter is .447797570…:

** ****.447797570… ****∕ .564189584… =** **. 7937**0052…

**∕ 1.0**

** ****now, compare the Great Architects Measures to Man’ Measures:**

** ****. 7937**0052… ∕

**.**5

__7937__**= .9999**3767…

And now, for the **64,**000 dollar question:

**WHO PLAGARIZED WHO?**

*Measures Of Land* showed us how the length of a *mile* can be expressed as:

**64**0” / [(**1.0** / .**99**) − **1.0**] = **1.0** mile (in inches)

and how a “square mile” of *exactly* **64**0 acres was derived by subtracting one course of **64**0” squares from each one of two adjacent edges of a square area (with edge) measuring **64**000” . The “difference” in *surface* *area* between this square area and the square mile was found to be **12.99**45923… acres. . . the same numeric quantity (different power) as the missing *surface area* (.**1299**60526) for each new sphere in the previously explained *one-into-two* spherical transformation. Its relationship to the *meter measure* and the *inchmeasure* can be seen in the equation below:

**1.0** / [2(.**1299**5…) + **1.0] = . 7937**1… /

**1.0**

** ** This **12.99**45923… “difference” in area, and its **. 7937**1… relationship to the meter, if rewritten as:

**1.0** / [(**12.99**45923… / **50**) + **1.0**] = **. 7937**1… /

**1.0**

leads us straight to the *hectare*, metric’s counterpart to the *square mile*:

[ 3(**10**) + **1.0** ] X [(**10**^{4} X **50** ) + **1.0**]** = 1.0 **perfect *hectare* (in whole units of square “__inches”)__

Note the similar aspects of the last two equations above, *and what they are describing*. Each one

*starts*with a square, subdivided into

**10,000**sub-unit squares. The top most equation, and its “difference” quantity as a measure of the amount of acreage

*removed*from its square, leaves the perfect

**64**0 acre square mile

*as its remainder*. And the lower equation (immediately above this paragraph)

*starts*with a square subdivided into

**10,000**sub-unit squares and then perfectly describes in square “inches”, one

*hectare*; a land parcel 100 “meters” by 100 “meters”.

Now, look at the following equation:

[1/32]” + [(**27**)^{1/2} / **640**]” = .**03936**8988…” = **1.0 ^{mm }**

**(.9999…fine)**

** **and compare it to this equation:

12 [{[24(**4.125**)^{feet}]^{2}}/**27**] = **4,356**^{ square feet} = **1.0 ^{square chain}**

The first equation shows the degree to which the quantity **27** commensurates *metric measures* with *inch measures* (**99.99**% perfect!). and the second equation __perfectly__ describes one square chain (or 1.0 acre / 10), again exposing the quantity **27** along side a **4.125** unit *as being at the heart of land measures*.

This next very simple equation uses powers of the same constants found in the two equations immediately above (**27** and **640**). It reveals the mathematics showing *exactly* how the *illuminati* (in the late 14^{th} century) designed the transition from the ancient Roman gallon of 216 cubic inches to the modern gallon of 231 cubic inches.

216 = 231 – 231**[ 27/6400] ^{1/2}**

## Deriving The Gram and the Grain

** **Several examples back we began to segway into the *gram* and *grain*, the measures of *weight* associated with the two different systems of modern measurement. History clearly and indisputably shows that the metric system’s unit of weight, its *gram*, is derived from a unit of *length* (1.0 centimeter). The *weight* *of pure water* contained within the volume of a cube having this *edge-length* is the *gram*. On the other hand, again according to history, the *grain’s* origin is *not* based on the length or *size* of any geometric unit, but instead *literally* on the *weight* of natural seeds, or “grains” . . . particularly wheat, barley, carob, and peas. Only much later did various kingdoms and empires create physical standards in metal, *allegedly* based on the weight of the grains.

The following simple geometry and associated mathematics will show that both weight measures, the *gram* and the *grain*, *are born from the same measure of* *surface area*, proving once again that hi__story__’s version of their origins is just that; a “story”. Here’s how it works:

Since weight is a property of volume, and *not* a property of surface area, the geometric *unit* (in this system of *transformational geometry*) begins with **1.0** unit of *volume* in the form of a perfect sphere. The reader should remember and reference the image on the first page of the chapter on *Measures of Land***,** where the naked spherical *volume* unit sits atop its own **1.0** unit of *surface area* rendered into a square. This same image, but this time *quantified *by the **1.0** *unit* being assigned to the spherical *volume* instead of its *surface area*, is where geometry gives birth to gra(**mm)** and gra(**im)**. The name that the *illuminati* chose to call this **1.0 ***spherical volume unit* of weight *is* the “gram**”**.

In geometry, *volumes can equal relative weights* if in the given system the volumes of all of the forms are comprised of the *same substance*. So any number of these spherical units, if of the same substance, will have the same weight . . . **1.0 gram**. And because two of these spherical weight units are required *at minimum* for any notion of “balance” to exist, the geometry of the *gram* and the *grain* begins with not one, but **2.0 grams** *in the form of perfect spheres*.

Spherical units each weighing **1.0 ***gram* is what quantifies this *first* system of weight. What I mean by “first” is literally being the *older *of the two systems. Of course, this is another historical *anachronism*; but after all, that’s why *they* called it a “*gram*” . . . as in “*gram*pa and *gram*ma”. Regardless of which one really came first, the second system, quantified in *grains*, is structured on the *exact geometric antithesis* of the first system’s spherical form. This is a regular tetrahedron. __This tetrahedron is so scaled that it is equal to the “face value” of the 2.0 grams__. This means that the

*surface area*of the tetrahedron, literally its “

*face*”, is equal to the

*surface*

*areas*of the two spherical

*gram*units. These geometric forms are depicted in the photograph on the following page.

The combined surface area of the two spheres is equal to the surface area of the tetrahedron. If each sphere is **1.0** “gram”, the tetrahedron is **1.0** “pence”. How do we know this?

The math and geometry supporting this assertion is as follows: In the photograph we see the two spherical *grams* and the previously described

tetrahedron. Ultimately, *we want to know how many grains are in the volume of the tetrahedron*. We already know each sphere is

**1.0 gram**, and that their two surfaces combined equals the surface of the tetrahedron. That’s all the information we need to answer the above question, and more.

The first task is to find the surface area of one spherical *gram* unit. Here again it is important to understand that in the eyes of geometry “the unit”, and the “name” of that unit, *creates* or *becomes* the measuring rod. For example, if instead of grams each of the two spheres was a cubic “foot”, then we would calculate their surfaces in units of “square feet”; or if cubic “meters”, then “square meters”, and so on. So the only difference by calling them *grams* is that our measuring rod is in “gram based” units.

The surface area of any sphere that is defined by having its volume equal to **1.0** *cubic* “any name will do” is 4.835975… *square* “any name will do”; which is also (**36π**)^{1/3}. So the *surface* *area* of the tetrahedron in *square* “gram-based” units is 9.671951… Now from this we can calculate its volume and find it to equal **1.5551**203… *grams*. . . and/or **23.999**173… *grains*. This is **24** *grains* to better than a **99.99**65…% approach to perfection!

In British history going back to the end of the “dark ages”, **24** *grains* was *itself* a “unit”. The “name” of this “unit” back then, and to this day, is **1.0** *pence*. So referring back to the previous photo, if the two spheres on the left are each **1.0** *gram*, then the tetrahedron on the right is **1.0** *pence*.

While the *gram* subdivides *only* into parts or powers of itself, such as tenths, hundredths, thousandths (milligrams), etc., the *pence* naturally subdivides into **24** equal “units” with each one equal to **1.0** *grain*. This is because the form of the tetrahedron, which represents the *pence* in this geometry, *naturally* subdivides its internal volume into **24** equal *volume* irregular tetrahedronal units.

The photograph above exposes the tetrahedron’s “natural” internal sub-divisioning.

Over three and a half decades have pasted since I first learned about this geometry studying Buckminster Fuller’s monumental work titled *Synergetics*. He named these sub-units “A Quanta Modules”. Many years ago, I had a special moment involving Dr. Fuller that someday I hope to share with others. It forever changed my life. But this I can say now, *unequivocally*; without Dr. Fuller’s creativity and genius this entire manuscript you are presently reading could not have been written.

In the photograph above, the tetrahedron has been “quartered” to its center point and one face-section-quarter has been exposed along with two sub-unit irregular tetrahedrons, a right and left handed version. There are two other pairs that have been left attached. (So as not to be confused, the two-quarter sections indicated at the lower left *are the same quarter *sections attached to a third one, as indicated in the upper right.) All of these reduce to “A Quanta Modules” and are of the exact same volume. Dissected in this manner, the entire tetrahedron is reduced into its 24 constituent parts. These 24 ** grains** are derived from the same

*surface area*as are the two spherical

**.**

*grams* This *is* the “pennyweight” of old. It is 1/20 of a troy ounce; but more importantly, 1/20 is “**5**” *hundredths* of a troy ounce. It is from *pen(ta)*, the Greek word for **5**, that gave its name to this unit of weight . And because of its role throughout history as a fundamental weight measure and money unit, later came the Latin word “pendare”, meaning *to hang, weigh or pay* . . . which led much later to such words as *pension*, *pendulum*, *pendant*, *penance*, *penny*, and many more.

To the *illuminati*, this became the “money particle”. This *pence* or *pennyweight* built the coinage on both sides of the Atlantic. In England by the end of the thirteenth century it was well established that twelve of these weights equaled one “shilling”, twenty shillings made a “pound” (troy). Of course, historically at that time the “gram” did ** not** exist, and the only unit of measure

*was*the “grain”. And precisely

**24**grains equaled

**1.0**pence. Our

*geometrically derived pence*, at

**1.5551**203024…grams equals

**23.999**173…grains and

*did actually exist*, not only way back

*then*, but

*as an ideal geometric form. And its weight*

__eternally__*is*

**24**grains, at least to a 0.

**9999**6… fineness in degree of perfection.

**The Troy Ounce of 480 Grains**

** ** The “illuminated” among the ancients probably knew what Dr. R. Buckminster Fuller re-discovered last century: that a regular tetrahedron naturally subdivides into **24** *equal volume* irregular tetrahedra. This *money particle’s* natural geometrical sub-divisions of irregular, long pointy tetrahedrons, when separated and loose in numbers actually *appear* to closely resemble “grains” of wheat or barley.

** **Whoever designed the pence from the combined surfaces of two **1.0** *gram* units in the form of two spheres, also knew that *perfect spheres* of uniform size and weight were far superior to grains of wheat or barley for use as fundamental units from which a *system* of weights is built. No matter how close in weight and size, cereal “grains” could never even *approach* the perfect uniformity of *idealized geometric spheres*. And of course the geometers of old were also well aware that the sphere was geometry’s choice for the most efficient packaging of volume, since it contains the most volume using the least *surface* *area* compared to any other geometric form.

** **They also knew the difference between the geometry at work in a bushel full of cereal grains compared to that within one full of comparable sized uniform spheres. By connecting with lines the centers of mass of each “unit”, grains in one bushel and spheres in the other, two very different geometries are revealed. The cereal grains create an irregular and mostly chaotic matrix. In contrast, in the bushel of spheres, each is surrounded by and perfectly tangent to **12** other spheres. Connecting the centers of the spheres creates what Dr. Fuller called an “isotropic vector matrix”, i.e. vectors or lines everywhere the same length.

Around any point within that matrix geometry accommodates one vertex from exactly eight *tetrahedra* and six *octahedra*. These are unobstructed spatial domains created within the individual confines of line sets. These two commensurate geometric regular polyhedrons both share identical face triangles, but the *octahedron* is four times the volume of the *tetrahedron*.

Geometrically speaking, the *matrix* formed in the bushel of spheres is seen to be full of nothing but tetrahedronal and octahedronal spatial domains, with no voids in between. The eight individual triangular faces of each octahedron is in turn one face of each of eight adjacent tetrahedrons. For every eight tetrahedrons there are three octahedrons occupying any given space. The entire bushel within, indeed all of space itself, could be filled completely using volume units in the shape of these two regular polyhedrons.

But this natural geometric sub-dividing of space itself does not end here. It comes full circle back to the original tetrahedronal form of the pence and its composition of **24** “grain”-like “A Quanta Modules”. If these be the sub-units within each of the tetrahedra within an *isotropic* *vector* *matrix*, then the adjacent octahedra, which share faces triangles with the tetrahedra, can **24** “A Quanta Modules”. Another way of looking at this is by imagining each of the tetrahedra within the matrix being incased by another ¼ tetrahedron from adjacent octahedrons on each of their four faces. This results in convex clusters of **48** A Quanta Modules (modeled on the right in the photograph below).

What is left remaining within each octahedron is a concave cluster of **48** (what Dr. Fuller called) “B Quanta Modules” (modeled on the left in the photo above).

The **48** “A” and “B” Quanta Modules comprising each of the forms are of identical volume. Each module is equal to one “grain” of the **24** grain tetrahedronal “pence” (derived from the surfaces, or “face value”, of two spherical “gram” units). That they are of equal volumes is easy to demonstrate. Divide the octahedron into eighths by cleaving it through its three square equatorial planes. Since the octahedron is four times the volume of the tetrahedron each 1/8^{th} octahedron equals ½ a tetrahedron’s volume. If we remove the ¼ tetrahedron from the base of the 1/8^{th} octahedron we are left with a volume equal to the ¼ tetrahedron but in the form of six “B Quanta Modules”.

The 1/8^{th} octahedron is depicted face-down on the lower right in the previous photograph. The two forms in the middle show the ¼ tetrahedron within resting tangent to one edge of a now tilted back assembly of B-Quanta Modules (exposing its concave interior). The assemblage of forms in the lower left corner show how four of the 6 B-Quanta Modules embrace a cluster of 6 A-Quanta Modules within to form together as the 1/8^{th} octahedron.

Now when the geometer looks into the bushel it is possible to see nothing but neatly arranged clusters of **48.0** identically volumed modules. They are of two types: *convex tetrahedra* and *concave octahedra*. They are interwoven together, and like a three dimensional fabric they fill all of space, leaving no voids. This unusual complementary geometry does not lend to repacking very easily. For this the geometers used another natural arrangement out of a combination of these two forms. These are *truncated cubical clusters*, with each containing a blend of **480** A and B-Quanta Modules. Archimedes called this shape the “cuboctahedron”; and later, Buckminster Fuller coined the term “vector-equilibrium” for this very special geometric solid. I am confident that the *illuminati’s* geometers chose *this* as model for their unit of weight measure, and that those at the time of its inception named it the “Troy Ounce” of **480** “grains”.

A few paragraphs back, when looking into the bushel with the matrix of connected sphere centers we saw a lineal frame work isolating individual tetrahedronal and octahedronal spatial domains. When these were again subdivided into grain-like modules with each equal in volume to every other, and a spatial domain unto itself, we saw another arrangement emerge from these clusters of **48.0** A and B Quanta modules. Remember, around every sphere center is a vertex from eight tetrahedra and six octahedra. The octahedra are naturally cleaved in half by the planes of the B Quanta modules of which it is composed within. Thus around any given vertex or sphere center a “natural unit” is formed out of the eight tetrahedra and six “one-half” octahedra. The resulting shape is a cube with its eight corners truncated (cleaved) from the mid-points of its edges. The entirety of space can be filled with these cuboctahedronal blocks with each containing **480** A and B Quanta Modules (336 A, and 144 B).

The parallels above between the natural “geometry of form” and the actual systems of weights and measures conform to a 0.**9999**6 fineness. In terms of “models”, the *tetrahedron* with its **24** natural subdivisions, and the *cuboctahedron* made from these *tetrahedra* and composed of **480** identical units, are both perfect models for the “pence” and “troy ounce” respectively.