The Occult’s Secret Chosen One


          This system begins with an ideal “unit” of weight. It is in the form of a cube, and this cube weighs 1 “unit”. Until we “name” the unit, the cube has no specific weight or volume (except for that relating to later quantitative constructs as the system develops). Now, this is not the time to explain why the illuminati chose this specific geometry to model their system, but for clarity it is important to first actually see how the system was formed and how perfectly it functions.

         Next, 27 of these units are assembled into one single cube, and then this new cube (as one single unit) is further sub-divided into 1000 mini cubes. Each of these “cubets” has a volume equal to .027 unit. The photo below shows the 1 unit cube; 27 assembled together as a single cube; this cube divided into a thousand mini-cubes; and, the single cubet itself.


          Up until this point none of these cubes have any size or any weight. We only know their relative volumes. But once we “name” the unit, (in this example) it becomes a weight. Then we have could have a pound, an ounce, a gram, a grain; some agreed upon weight, with an agreed upon name, in the form of a cube. And until we assign some actual substance to the cubes, they still won’t have any meaningful size. For purposes of building the system, only the named weight unit is required. The “gram” was the name the illuminati chose and assigned to the beginning cube, and to each one of the 27 assembled together. So now it can be said that any one of the 1000 cubets must weigh .027 gram, or 27 milligrams.


          Using these 27 milligram cubes, and both perfect and perfectly-imperfect rectilinear geometric constructs, over time they devised the systems of weights and measures for all of humanity. Among the first of their works was the Troy Ounce of 480 grains. Many centuries later, they imposed on humanity another 437.5 grain Avoirdupois Ounce. Some reading this are probably aware of the blatant contradiction in the above narrative since history tells us “grains”, and both ounces built from grains, had been in use long before the French Revolution and the “invention” of the new “gram” unit during the bloodbaths and beheadings. Yet, despite this historical record, I contend that knowledge of a unit we now know as a “gram” had been well known to the ancient “illuminati”. I can say this with some confidence because, as we can clearly see from the modeling, these two “quantities” are intimately related. In fact, they even share a single common geometric core.

The Troy and the Avoirdupois Ounces and a 27 milligram cubet

          Depicted in the photo at left are both the Troy and Avoirdupois ounces. They are modeled by perfectly complete rectilinear cuboids comprised of 27 milligram cubets. Historically they have no known special relationship to one another. Allegedly these weights were arrived at by thoroughly arbitrary and subjective processes such as feeling like the “right” amount, or by decree of some king. In the picture, one can clearly see that both ounces share a “common core”, which is define by the white cubes in both columns.

          Now let’s look at each of the two ounce columns and associated math. The Troy ounce on the left has 6 cubes by 8 cubes forming its base, and is 24 cubes high. There are in all 1152 cubes (6 X 8 X 24), each with a weight of .027 gram.

1152 X .027gram = 31.104grams

          The number of grams in a Troy ounce was finally determined by agreement among the nations of the world after reaching an agreement on how many grains are contained in one gram: 15.43235835 grains. Therefore, the ancient Troy ounce of exactly 480 grains contains 480grains / 15.43235835grains/gram  = 31.1034768grams. This compares to the ideal modeled weight in grams as:

    31.1034768 / 31.104 = 0.999983179…

          By comparison, the column modeling the Avoirdupois ounce (on the right in the photo) has a base measuring 6 cubes by 7 cubes and is 25 cubes high. There are 1050 cubes in all, each with a weight of .027 gram:

1050 X .027gram = 28.35g

          Again, just like with the Troy ounce above, The Avoirdupois ounce of exactly 437.5 grains contains 437.5grains / 15.43235835grains/gram = 28.349523125grams. And this compares to the ideal modeled weight in grams as:

28.349523125 / 28.35 = 0.999983179…

          Nobody can deny the elegant beauty and simplicity, let alone the accuracy of these models. If one begins with their common core of white cubes alone, it is easy to see that one need only add one complete course to one of this cuboids faces to get one of the ounces. If instead, another one of its faces is covered with one complete layer, then like magic, there is the other ounce. And as for the “core” of 1008 of these cubets, and its 420 grain weight; much more will be said about this special quantity later.

          Now for any skeptics who would attribute this all to “coincidence”, keep in mind that already there is more than just one of these coincidences. For example, it might be coincidence if both ounces just happened to be capable of perfectly complete cuboid modeling by the same little cubet, but resulted in two unrelated cuboid models. But that in reality they are opposite face modifications of the same “core” column of cubets; and that both “historically unrelated” ounces mirror their respective modeled counter-part weight-measures to the same identical degree of perfection: 0.999983179…; and if in 1588 Queen Elizabeth had not “coincidentally” increased the weight of the avoirdupois pound from 6992 to exactly 7000 grains, then posterity would have been spared that awkward ½ grain in their present 437.5 grain ounce and would make all of the previously demonstrated modeling impossible and simply obliviate any notion that these quantities are purposely related through geometry. Forget about coincidence in this case.

          And surely any further notion of coincidence will be laid to rest once this following question is answered: why did they purposely choose 12 ounces for the Troy pound, and 16 ounces for the Avoirdupois pound? My research comes up empty for any reasonable historical answer. But I believe I have found the real reason in the geometry that is revealed when we arrange these respective “ounce” quantities of 27 milligram cubes in some particular fashion. Let’s have a look at why these quantities of 12 and 16 ounces were really “chosen”.

Why 12 Ounces in A Pound Troy And 16 Ounces in an Avoirdupois Pound

          In the photo below is a perfect cube made from 13,824 “cubets”. There are 24 cubets per edge. Each little cubet weighs .027 gram. Therefore, the total weight of this cube in grams is

13,824 X .027gram = 373.248grams 

One Pound Troy

In “grains”, 373.248 grams equals 5760.09688… grains (note 373.248grams X 15.43235835grains/gram = 5760.09688…grains), and there are 5760 grains in a pound Troy:

5760 / 5760.09688… = 0.999983179…

          The “perfect” cube in the photo is one pound Troy. The 12 columns delineated by the red lines are 12 of the Troy ounce columns of 1152 cubets shown on the left in the previous photo. This complete and perfect geometry is why there are12 ounces in one pound Troy.

          The geometry of the Avoirdupois pound of 16 (437.5 grain) ounces is also modeled on the cube, although a little differently. In the photograph below each of the two “cuboids” depicted equal ½ pound, which is 3,500 grains (there being 7000 grains in 1 pound AV.). These are cube-oids and not cubes because each of the two perfect cubes (depicted by the white 27mg cubes in the photograph) has 1 additional complete layer of sub-cubes added to one face. In the photo these two layers are highlighted in red.

1 Avoirdupois Pound

          Each of the two perfect cubical assemblages is a cube with 20 cubets per edge. With the additional course of red cubets, each cuboid then measures 20 X 20 X 21 cubets/edge, or 8,400, and weigh ½ pound AV since

   8,400 X (.027gram) = 226.8grams,


3500grains / 15.43235835grains/gram = 226.796185grams


226.796185grams / 226.8grams = 0.999983179…

          Thus the Avoirdupois pound is seen to perfectly model the geometry pictured above exactly to the same (better than ten-thousandth) number place as the supposedly unrelated centuries older Troy pound when it too is modeled by the same 27mg cubets.

          Later in this manuscript, the modern “gallon” unit of volume measure, which is based on the cubic inch, will be shown to have identical modeling properties.

Additional Models of the Troy and Avoirdupois Ounces

The Troy Ounce modeled by (1152) 27mg cubets

          This is a very simple model to imagine: two-thirds, or .666… of a perfect cube which itself is comprised of 27mg cubets. It has 12 of these cubets per/edge, and 1728 form the complete cube. Two-thirds of 1728 is 1152 cubets. A few pages back is pictured 1152 cubets stacked as a 6 X 8 X 24 cuboid column identified as one Troy ounce. Pictured above is the 12 X 12 X 8 cuboid which is an alternative model of this 480 grain unit of measure. Again, here is one complete course of red cubets atop 1008 white cubet. And again, a few pages back, 1008 cubets was shown to be the common core of both ounce columns, and would become the future 420 grain U.S. Trade Dollar. Divide in half this core column (of 24 courses, each with 6 X 7 cubets/edge) and re-arrange the two halves into the white cubet portion depicted in the above photo. Then, almost like magic, by adding one perfectly complete layer to the appropriate face of this re-arranged ounce column and the Troy ounce is again produced.

         The cuboid in the next picture consists of 1050 cubets weighing 27mg each. They assemble in a 7, 10, and 15 per/edge cuboid. Again, 1050 cubets were previously shown to weigh one Avoirdupois ounce of 437.5 grains.

The Avoirdupois Ounce modeled by (1050) 27mg cubets


          In this case, the one complete course of red cubets leaves 900 white cubets beneath. This is significant as it is this assemblage of white cubets that unifies the Avoirdupois ounce and the American silver dollar coin in the same way that the 420 grains of the Trade Dollar as a tall slender column unified this same A.V. ounce with the Troy ounce. Let’s have a look at the geometry just described.

The Silver Dollar, the Avoirdupois Ounce,

And the Accounting System

Based On the 27 Milligram Cubet

          History clearly tells us that there is no “special” relationship between the gross weight of the silver dollar coin and the Avoirdupois ounce. According to the historians, both measures were arrived at arbitrarily and subjectively. This is simply untrue. Its not that the historians have been lying to us, the world’s peoples, but that they (the historians) have been lied to through out the ages. As it is often said today with all things computer related, “garbage in, garbage out”. As for history, I’m convinced that most of what is really important is never disclosed, or it’s simply covered-up with a lie. Most of history, because of what I now know, is certainly corrupted “garbage” designed for, and fed to the masses of unaware people. Most of history is beyond repair.

         The same group of unseen deceivers assured the implementation of these specific weights. In so doing, they were literally enshrining an occult science into the emerging world-systems of weights and measures, and especially into the new American coinage. For into this coinage, using geometry, they would (in their minds) imbue magic and power. In this way, beginning with the 1792 Coinage Act they created a system of coinage that (they believed) would gain precedence over all other monetary systems.

         The photograph below shows the 900 white cubets (highlighted in the previous picture of the Avoirdupois ounce) assembled as a single cuboid. It is situated between the 437.5 grain A.V. Oz. to the left and a weight of 412.5 grains to the right. Of course, 412.5 grains is the weight of the American silver dollar

The Avoirdupois Ounce and Silver Dollar with Common Core Between

           This picture clearly shows how the same cuboid, by adding one complete additional layer of 27mg cubets to the appropriate face, becomes in the one case an Avoirdupois ounce; and in the other case, the silver dollar’s 412.5 grain weight measure.

         These simple formal transformations conclusively prove that there is an inseparable geometric/mathematical affinity between these two quantitative measures that is inherently built into this natural system of geometry. They simply are not arbitrary quantities to geometry and mathematics, nor were they arbitrary to the group of illuminati who steered their acceptance through the various legislative bodies over the course of time.

         Further proof, if any more be needed, that the Avoirdupois ounce and a weight of 412.5 grains are in fact “geometric siblings”can be found in the simple line, which gives birth to both quantities. Here’s how it works.

         In the photograph below are two polyhedrons. Both are made from the same line in


the sense that the sum of the edgelengths of each form are equal. In fact, in the eyes of geometry the two forms are 1st dimensional equivalents. Now if the cube is made out of one Avoirdupois ounce of American coinage silver, 437.5 grains, then the weight of the tetrahedron made from the same metal will have to be 412.47895… grains. And this is 412.5 grains to better than 99.99% perfect commensuration.

412.47895… / 437.5 = .9999489…

          This is simply the way geometry itself inherently operates. This is a view into the geometry of form. This is not taught to the peoples of the world for a reason. It is not taught, because to do so would expose an unimaginable level of deception, not only with respect to our weights and measures, but to our understanding of science and history as well. Remember just as E = mc2 , knowledge = power.

 Modeling the Silver Dollar Coin

Using the 27mg System


          There is more than one way to model 412.5 grains, in a perfect and complete geometric form, using nothing but 27 milligram cubets. The photo above is one manner of such modeling. The white cubets is the common core shared by the Avoirdupois ounce, as was just illustrated two photos back. But there is another modeling form that was specifically chosen for the American silver dollar. In this assemblage the cubets arrange in 10 layers, with 99 in each layer. The photo at left below illustrates this modeling.


          They chose this modeling for at least two reasons: the first is that the perfect cuboidal assemblage of white cubets beneath the red (891 of them) weighs 371.25 grains. This is the exact amount of pure silver in the silver dollar coin. The remaining layer of red cubets (99 of them) weighs 41.25 grains and is the amount of copper alloy in the coin. Look at the next photograph below. What you are looking at is the recipe, or formula for .900 American “coinage silver”.

          Both of these metal’s quantities (371.25 and 41.25) are very special to the geometry of form. So too is the 9/10 ratio also an integral part of geometry’s structure. This is clearly demonstrated by the following very simple forms. They reveal essential structuring which goes back to the very foundation of geometry. This “structuring” is based on geometry’s preferred forms for the three powers of the fundamental unit in a three dimensional space frame.


          The graphic to the right depicts the view looking at the leading edge of four tetrahedrons; 1 large red, and 3 smaller blue tetrahedrons. Now for scale, imagine a single line equal to 1.0 unit in length having been reconfigured into the six edges of a blue tetrahedron. That means each of the blue tetrahedrons is considered to be 1.0 unit of length in the form of a tetrahedron’s edges. In this way the one-dimensional line is transformed into a three-dimensional form.

          The edges of the red tetrahedron are formed from three of these 1.0 unit-length lines. As we see in the graphic, the combined height of three “unit length” lines in the form of three separate tetrahedrons’ edges equals the same exact height as the same three lines together when forming the edges of a single tetrahedron. Again, this is a geometric “law, in a manner of speaking.

          Now, imagine a square that is the same height as the tetrahedrons. If this square is one of the six faces of a cube, then that cube measures 1.0 surface unit (or square unit) in the form of a cube’s surface. With all due respect to Euclid’s units as line and square, the geometry of form prefers the tetrahedron and cube for 1st and 2nd dimensional accounting purposes in a three-dimensional space frame.

Obviously “geometry” appreciates this commensuration of fundamental quantity and form. But how does this relate to the silver dollar coin? Here’s the answer: if we change the scale and make the red tetrahedron 371.25 grains of pure silver, then each of the blue tetrahedrons are 13.75 grains of pure copper, or 41.25 grains all together. If you combine these four metallic tetrahedrons together what you get is the exact amount of the metal alloy for one silver dollar coin. Once again, like the cuboid in the previous photograph, this is the recipe for America’s .900 COIN SILVER. It is inherent to the geometry of form.

The Silver Dollar and the $10 Gold Eagle



          The 1792 Coinage Act created a $10 gold coin. It is called the “Eagle” and it weighs 270 grains. America’s first gold coins  are 22 karat which is to say that these gold coins are 11/12ths pure. This means that the Eagle contains exactly 247.5 grains of pure gold.

11(270grains / 12) = 247.5 grains

          The silver dollar and eagle are depicted in the photo to the left The silver coins are 9/10ths pure silver. Once again, this modeling reveals the same visual and geometric design themes at work here in the1790’s and early 1800’s as with all of the other key weight examples shown thus far going all the way back to the nearly ancient troy ounce. And just as the layer of red cubets indicates the 9/10 alloy ratio of the silver coin’s cuboid (depicted in the foreground), so too does the complete layer of red cubets indicate the 11/12 alloy content of the gold coin’s cuboid nestled behind.

          It is clear from the picture that the cores of these two coins are intimately related. The white cubets, which depict each of their respective pure metal contents, are these two cores. In 1792 it was claimed that the exchange ratio between gold and silver globally was 1:15, which translates to 0.0666…, a power of 2/3. One grain of gold would buy you fifteen grains of silver.

          Now a $1 gold coin would theoretically weigh 27 grains. If modeled by 27mg cubets, it would have one tenth the number and be much smaller than the cuboid in the photograph. That’s why when increased to a $10 coin, its core becomes two-thirds, or .666… the silver dollar’s core. In this manner their geometry is replicated.

          But this is only where the unique properties of this weight measure chosen for the Eagle coin begins. Remember, at the heart of this system of weight measures are the grain and the gram. And as we’ll see next with the 270 grain Eagle coin and its 648 cubets that comprise its perfectly complete cuboidial form, it literally mirrors the micro-modeling that links the gram and grain from the very starting point in that one greater occult system from which both were derived. Have a look.

Original American Eagle Coin Models The “Grain”  In The System Which

Gave Birth to the Weight Units Known as the “Gram” and the “Grain”

The 648 White Cubets Model 270 Grains

          Another of the many reasons the weight of 270 grains was chosen for the $10 gold Eagle can be seen, once again, in its modeling geometry. In the photograph above we see a perfect cube assembled from 27mg cubets, with 9 cubets/edge. Remove one complete layer from any face (in red) leaves the white “cuboid” portion. It is comprised of 648 cubets: 9 X 9 X 8 = 648. Since they each weigh 27mg the cuboid weighs 17.496 grams. At 15.43235…grains/gram it also weighs 270.00454.. grains, and:

270grains / 270.00454… grains = .99998317

          But probably even more significant is the Eagle’s formal relationship to the grain itself when viewed in the modeling system from which was also spawned the unit that (today) we know as the gram. Remember, an ounce measure is a natural “unit” only in systems based on the grain and pound. On the other hand, the gram’s first natural aggregated measure is the kilogram, and it sub-divides into milligrams. This is the traditional view.

          Here is the occulted view. Start with a perfect cube which itself is comprised of 1000 mini-cubes, i.e. 10/edge. Quanta-size its volume as = 0.1. Therefore, ten of these cubes together in one system gives that system a volume = 1.0. Now introduce a second cube comprised of the same mini-cubes but with only 9/edge; then, remove one complete layer of mini-cubes. Though it is a diffent size, this remaining cuboid is the same cuboid in form and quantity that models the Eagle coin depicted at left. The (as yet sizeless) forms just described in this paragraph are depicted in the photograph below at right.



          Now it is time to assign scale to these forms. Since, by previous definition, the ten cubes in the background total volume 1.0, or more descriptively, “10/10 volumetric unit”; then by comparison, the lone cuboid’s volume must be 0.0648. But there is still no scale until a name is assigned to that 1.0 unit. The Illuminati called it their “Gram”, since it is in fact the grampa of all weight measures that followed. And just how close to the perfection of these geometric ideals do the measures of today actually conform? As we can see below, much too close for coincidence.

1.0 / 0.0648 = 15.432098… / 1.0

 and, there is 15.43235835…grains/1.0 gram

 15.432098… / 15.432358… = 0.999983179…

          In fact, to demonstrate this is not just some cute foible (that we find the image of the grain itself replicated in the Eagle’s modeling) I will at this point indulge the reader with a glimpse of just where this narrative will soon take us. So with out actually going down this “fork in the road” just yet, we will pause momentarily and take a peak at where it begins.

(A Momentary Pause at a Fork in the Road)

          Thus far we have been traveling a pathway that shows us where humanities measures of weight have originated. There we have seen that quantities specific to American gold and silver coinage such as 371.25, 412.5, 270, and 247.5 to be quantities inherent to “geometry” itself. This momentary detour takes us to where the measures of length originated, i.e. the present world’s two systems based on the millimeter (mm) and the inchmeasure (im). Get out your calculator because you probably will find this hard to believe.

         Of course, we are reminded that history tells us there is no intentionally designed relationship between these two systems, the one very old and the other relatively new; except, of course, for the ratio calculated (after the fact) for converting the one into the other. Over time it was determined that the two systems would be commensurate at a fundamental unit of length (called an “inch”), and that it contained exactly 25.4 millimeters or exactly 32 inchmeasures.

25.4 / 32 = 0.79375

          Multiplying the number of inches by 25.4 gives the number of millimeters; dividing the number of millimeters by 25.4 gives the number of inches. The number 0.79375 is telling us that one inchmeasure (1/32) is only 0.79375 the length of one millimeter. This is overtly what we end up with. But covertly there is something else altogether going on.

         To the ancient illuminati who first discovered the geometry of form, and have kept it an occulted secret ever since, the two measuring systems relate as:

(2.0 0.4125) / 2.0 = 0.79375

          By now it must be pretty obvious that there is something going on here. The single quantity distinguishing the two systems of length measures, 0.4125, is the exact quantity essential to understanding the two systems of weight measures. In fact, the entire system that I have come to call the “inchmeasure” is itself based upon this 4125 quantifier, which we will soon see is inextractibly woven into its very fabric. For example, overtly a .4125 portion of one-foot is 4.95 inches; and, 49.5 inches is 4.125 feet. Also, 4.95 inches is twice 2.475 inches which mirrors the 247.5 grains of pure gold in the $10 Eagle coin.

         As this manuscript progresses, the reader will come to see that America’s entire system of public land measure, and much of the world’s as well, from the mile to the acre, is literally based on these quantities of 412.5, 371.25, 270, 247.5, and their derivatives. And remember, each of these quantities have been shown to be among the essential measures defining America’s gold and silver coinage.

The Geometric Origin of


And It’s Imprint In Natural Structure

          To the general public a “ton” is simply 2000 pounds. These are avoirdupois pounds, and since each pound equals 7000 grains a ton is also 14,000,000 grains.

         It could easily be concluded that this ton measure arose as the result of needing a “convenient” unit for large aggregations of pounds. And that they designed this measure in baseten could be viewed as just another added advantage of convenience. If this is in fact the case, then we really should not expect anything of significance to be found by looking any deeper into this particular measure of weight. Let’s have a look anyway.

         We are aware that the “27 milligram cubet” has already been exposed as being the base unit of the illuminati designed systems of weight measures thus far studied. Maybe by modeling this ton measure with these cubets we can unveil even more mysteries.


         In this 27 milligram system of weight measures a single “cubet” weighs 27 mg.; but, it also equally weighs .416673676… grain (which can also be expressed as 1 / 2.4 grain to better than .9999 fine). In this system, 14,000,000 grains, modeled in cubical .416673676… grain units, requires 33,600,000 cubets. The previous sketch reproduced here from my notes reveals the first of many surprises regarding the “ton”.

         Is it coincidence or by design? A perfectly complete cuboid can be assembled from 33,600,000 cubets? Moreover, the proportions of this cuboid are the exact same quantities defining the number of grains in each of our “ounce” units. Thus in 27 mg. cubets, a 1.0 ton cuboid will measure precisely 160 layers of cubets with each layer 480 cubets by 437.5. Each layer weighs 12.5 pounds. (Note: 437.5 grains equals one avoirdupois oz., and 480 grains is one troy oz.)

         After noting the above, my next thought was the realization that 160 is a third of 480. I could stack two more cuboids atop the one in the sketch and have an even more perfect and complete cuboid. This 3-ton assemblage measures 480 X 480 X 437.5 cubets and is depicted in the following sketch.


          There was something else I noticed that seemed to make this specific measure of weight significant and unique with respect to both systems based on the grain. . . much more so than the single ton, or two tons.

1 Ton = 32,000 Av. oz.s or 29,166.666… Troy oz.s

2 Tons = 64,000 Av. oz.s or 58,333.333… Troy oz.s

3 Tons = 96,000 Av. oz.s or 87,500. . .  Troy oz.s

          Whereas 1 and 2 tons create irrational numbers of troy ounces, 3 tons creates whole unit amounts of both ounces. In fact, 3 tons can be seen as equaling:

(2000 X   480) Avoirdupois oz.s, or:

(2000 X 437.5) Troy oz.s

         It is clear to see from the data above that 3 tons perfectly unites the two systems of weight measures based on the grain. Aside from the grain itself, these two systems have no known historic relationship to one another, yet they clearly are intimately related.

         Again, referencing the drawing immediately above, one can’t help but notice that in the 27 mg. cubet system of weight measures, 3 tons model as an incomplete cube. The complete cube is an ideal form to which the actual assemblage only approaches; and it measures 480 cubets on all its edges. And (480)3 equals 110,592,000 cubets compared to the 100,800,000 cubets comprising 3 tons. Thus, the ideally completed cube compares to the 3.0 ton cuboid assemblage as:

100,800,000 / 110,592,000 = .91145833… , and

1 A.V. oz. / 1 Troy oz.     = .91145833…

showing that 3 tons is to an avoirdupois ounce, as 3 tons plus 582.86694pounds is to the troy ounce. This 582.86694pounds is the amount required to complete the cube (Note: 9,792,000 cubets is the difference between the two assemblages; multiplied by .027 gram cubet = 264,384 grams; times 15.4323…grains/gram = 4,080,068.63…grains; divided by 7000 grains/pound = 582.86694… pounds).

         Shortly, we will return to this seemingly odd quantity and see the important role it plays in our understanding geometry’s influence not only on the measures of man, but nature’s as well.

The Ton

The Meter Measure, and

The Element Pure Gold

          Imagine a cubic meter of pure gold. Each of this cube’s six square faces measures exactly 1.0 square meter and each of its twelve edges are 1.0 meter long. According to All Measures .com (a research resource site for engineers and scientist), and corroborated by other sources, pure gold weighs 19,300 kilograms per cubic meter.

         This time imagine 1.0 ton of pure gold. Unless you know something about gold, this is harder to do than imagining a cubic meter of . . . anything. A cubic meter of any substance is always the same size. But it is helpful to our imaginations when we find that 1.0 ton of gold is equal in volume to:

                                                                                                         .04700518… cubic meter

                                                                                                                1.3339… bushel

                                                                                                                47.005… liters

                                                                                                                99.334… pints

           All of these quantities were familiar to me as they are found throughout the geometry of form. It seemed odd to me seeing them here together, not only as man’s measures, but applying to gold as well. These units seem to be discrete, in the sense that they are distinct or clearly defined with very little residual. 1.0 ton of gold is equal in volume to 4/3 bushel to a very, very close tolerance. Likewise, it is the volume of 47 liters, as well as 1/3 of 298 pints. The actual measures correspond to their whole number ideals to better than .999 fine. It certainly appears there is something going on here that is inexplicable in light of our current understanding of history and science. Why is gold so neatly accommodating to man’s arbitrary measures?

         Of the four equivalent measures above, it was the 1.0 ton of gold’s volume as a portion of a cubic meter that really caught my attention (of course the liter follows from the meter). This is a very special volume quantity in transformational geometry. This is because when 1.0 surface unit, in the form of a sphere’s surface, divides its volume into two new spheres, each of the new spheres will have a volume of .047015799… cubic “unit” (by whatever name is assigned to that unit). Obviously, this means that the volume of the original sphere before dividing is .094031597… and that the area of its surface is 1.0 square unit.

         To me this is amazing, because it means that if 2.0 tons of gold has a volume equal to .0940103… cubic meter. . . then this precise amount of gold, if molded into a perfect sphere, will create a surface area equal to .999849… square meter. (Note: the length of a meter is 39.37007874 inches exact, and a square meter equals 1550.0031 square inches.)

         Here now is the model I saw coming into focus. We started with a cube and designated it our system’s unit. Its’ edge is 1.0 unit long, and each square face plane is 1.0 square unit. By naming this unit a “meter” we introduced real-world scale on to the cube. If now we create a sphere with a surface area equal to any face plane of the cubic meter, this sphere’s surface area will equal exactly 1.0 square meter. Its volume is now .094031597… cubic meter. If this volume is pure gold it weighs 4000.9740… pounds; or equally 2.00045… tons.

         The geometry tells us that the “ton” measure is the unit with respect to weight. And that it is the “meter-measure” that is the natural unit of length, area, and volume. These supposedly unrelated units, the meter and its derivatives and the grainbased ton and its derivatives, become integrated into one commensurate system ultimately based on a unit of substance: pure gold.

         There is another geometric model that applies only to 3.0 tons of gold. This model is “complete”, and more elegant than the cuboid made earlier from the 27 milligram cubets (which models the 3.0 ton measure of any substance). In “The Geometry of Form” it is called “the cylinder of maximum volume” and is a geometric ideal capturing the most volume with the least surface given the cylindrical form. Now we’ve already seen that 2.0 tons of gold contained within a sphere has a surface measure of 1.0 square meter. If this sphere is then encapsulated within the smallest cylinder in which it will fit, like a ball in a tin can, the height and the diameter of the cylinder are equal to the diameter of the golden sphere within (which is bluish-green in the illustration below). In geometry, a cylinder of this proportion is the cylinder of maximum volume. When the surface area of the cylinder holding the sphere of gold is calculated, its side area is found to be 1.0 square meter; and each of the two circular ends measure .25 square meter.


         So far this model has two forms: the 2.0 ton golden sphere and the enclosing cylinder. But the negative space inside, the void surrounding the enclosed sphere, is a third form. And if instead of void this space is filled with pure gold . . . it will weigh 1.0 ton. Now we are modeling 3.0 tons of gold within a surface area of 1.5 square meters.

         With two different geometric forms, and the exact area measures of 1.0 and 1.5 square meters, 2.0 tons and 3.0 tons of pure gold can be packaged with near mathematical perfection. To be exact, 3.0006776… tons of pure gold is contained within the cylinder of maximum volume form if its surface area measures exactly 1.5 square meters.

         Let’s now revisit the cuboid and cube that earlier in this chapter were constructed from the 27 milligram cubets. The cuboid, which is the nearly complete cube, models 3.0 tons and contains 100,800,000 cubets (480 by 480 by 437.5 cubets). The completed cube (480 by 480 by 480 cubets) contains 9,792,000 additional cubets adding 582.8669pounds to the cuboid’s initial 3.0 tons. How this quantity models and interacts with the fundamental geometric units distilled thus far from the properties of gold, again is simply amazing. Take a look . . . in your mind, of course, and follow along as I try to describe what I am seeing.

         First of all, by now we should know from all of what has transpired in the previous chapters, that geometry is trying to tell us “something” with this difference quantity. First, let’s look at it as the weight we know it to be; and that is 582.8669pounds (regardless of what substance). But this is also 4,080,068.630… grains:

4,080,068.63… grains / 480 grains = 8,500.1429… troy oz

         This equation resolves a very non-descript number of pounds into a near perfectly discrete number of troy ounces. And this is from a number that was deduced from modeling a 3.0-ton quantity using the illuminati’s 27 milligram system of weight measures.

         So far we have been working with a weight of 582.866…. pounds. Before we can investigate a size, a physical volume, this weight must be assigned a named substance. Of course, for purposes here, gold is the name of the substance weighing 582.866…. pounds, or equally 8,500 troy ounces. Now we can calculate its volume.

         First we convert the number of pounds into grains by multiplying by 7000. This quantity is divided by 15.43235…, the number of grains per gram, giving us the number of grams in 582.866… pounds: exactly 264,384 grams. Divide this quantity by 1000 and we have the number of kilograms: 264.384. Since this is the weight of a specific quantity of gold, and since gold weighs 19,300 kilograms per cubic meter, by dividing

264.384 kg. / 19,300 kg./m3 = .013698653… m3

we arrive at the physical size of this 582.866… pound unit of gold. In “round numbers”, so to speak, it is .01370 cubic meter.

         This number defines a volume quantity of gold. At this point, it is without any specific form. But to geometry, it can be the volume of a geometric form that is essential for maintaining surface and volume accountability as a result of geometric transformations. One such typical transformation is fusing the volumes of two units into one unit. Because of the more efficient “packaging” (in a single form), less surface area is required to contain a given volume. Now, let’s look at the 2.0 ton sphere of gold, with its 1.0 square meter surface area, and see what happens when it fuses its volume with another sphere’s volume identical to itself.

         Each of these spherical volumes of gold is .0940cubic meter; so the volume of the new (4.0 ton) sphere of gold is .1880cubic meter. Its surface area is 1.5874010square meters, and is equally expressed as [(4.0)1/3 m2]. This surface is .41259894… square meter less than the 2.0 square meters originally containing the 4.0 tons of gold in the form of the two separate spheres. Out of all the forms to choose from, geometry configures this “excess surface area” into the form of a regular tetrahedron’s surface. The volume contained inside this surface area is .01370203… cubic meter (m3). If this is a unit of pure gold it will weigh:

.01370… m3(19,300 kg/m3 ) = 264.44… kg = 583.01…lbs

         Remember that the 3.0 ton cuboid model (made from the 27 milligram cubets and discussed back on page 140) fell shy of being a perfectly completed ideal cube And that the volume of this ideal cube with 480 cubets/edge was shown to be 3.0 tons, plus 582.8669471… pounds. Now let’s compare this weight (calculated from the system of 27 mg cubets) with the weight immediately above derived from the pure geometry resulting from the fusion of two spheres of pure gold (with their surfaces each perfectly scaled to 1.0 square meter) into a single sphere.

582.8669471… pounds / 583.0107353… pounds = .999753…

         Before moving on, let’s take an inventory of the solid gold geometric forms thus far distilled from mankind’s “ton” measure of weight. Our first clue that there was something special going on was the volume of 1.0 ton in cubic meters: .0470…m3. It was because of my years researching the geometry of form that I immediately recognized this quantity as one-half the volume of a sphere with a surface area equal to 1.0 “unit”. This led to the realization that if 2.0 tons of gold is contained within the surface confines of a sphere having a .0940… m3 volume, then its surface area must equal 1.0 m2. Next we found the 3.0-ton packaging using the cylinder of maximum volume having a 1.5 m2 surface area.

         Slamming two of these 2.0 ton golden spheres together fused their gold into a single sphere of 4.0 tons. In this transformational process, there is an “excess surface” quantity amounting to .41259894… m2.


          We now know that if this surface area is in the form of a regular tetrahedron’s surface it will encompass a volume of .01370… m3. And, that this volume of pure gold weighs 583.0107… pounds; which as we previously calculated is also (just coincidentally??) the weight in pounds (582.866…) modeling the difference quantity separating the 3.0 ton cuboid (made from the 27 milligram cubets) from its implied ideal completed cubic form. In the graphic above, this tetrahedron sits atop ½ of a 2.0 ton sphere of gold.

         On the left is the plan view of the (hemi)sphere and tetrahedron. One cannot help but notice how closely the three tips of the tetrahedron’s base correspond to the circumference of the sphere’s cross-section. This is a physical or formal commensuration.

         The right hand side of the illustration is a frontal view of the tetrahedron atop the 1.0-ton hemisphere. We also see the X-section of another sphere having its surface area equaling ½ square meter. Note that its diameter is the height of the tetrahedron; this makes it physically commensurate to the tetrahedron, just as its’ ½ m2 surface area makes it commensurate to the hemisphere’s ½ m2 surface area (atop of which it sits). The volume of this sphere is also imprinted with some interesting geometric constants.

         For example, the cube of its radius is .007936704… The essence of this quantity is .793700526… which, as we have seen in a previous chapter, is geometry’s inherent constant defining the lineal relationships underlying volume transformations. Moreover (again, as we have seen earlier) it exposes the “metric/inch” relationship that is at the very heart of geometry itself:

32 X .7937005…mm = 25.39841.. X 1.000..mm = 1.0 “


25.39841…mm / 25.4 mm = .9999376

           Note: There are exactly 25.4 “millimeters” per inch; or 32 “inchmeasures” per inch, and 25.4 / 32 = .79375 / 1.000

         Interestingly, I see silver measures in the volume of this 2nd generation golden sphere. Its’ volume is .03324519… m3; and since it is pure gold, its’ weight is .03324519… X 19,300 kg/m3 = 641.632167… kg; or 641,632.167… grams. This is also 9,901,897.53… in grains. In the illuminati’s 27 mg weight system, 990.0000 cubets weighs 412.50693… grains, which is the gross weight of the American silver dollar coin. We can say that this sphere’s weight is 9,900,000 grains to a .9998… degree of exactitude. This is the weight of 24,000 silver dollar coins. If we want to be precise, this sphere is the weight of 24,004.6… silver dollar coins.

         Further confirming this inherent relationship between silver “coinage measures” and these specific weights in gold is seen when the same weight is expressed in troy ounces: 20,628.93780… Once again, this is 20,625 troy ounces to a .9998… degree of exactitude. This means that two such spheres of gold weigh 41250 troy ounces to this same .9998… degree of exactitude.

         We can see silver’s coinage measure even when this .03324519… volume quantity appears as a surface quantity in the form of a cube. This cube’s volume of .000412445… is a .999866… facsimile of the silver dollar coin’s quantity of 412.5 grains. This is not coincidence; this is how the geometry of form is “quanta-sized”.

          Now, there is also a geometric reason not to be surprised that the weight in pounds of this golden sphere with a surface area measuring ½ m2 is (to a .9999489… degree of perfection) 1000 times the square root of two units (2^1/2); which is 1,414.21… pounds; 1,414.55… pounds is its’ precise weight. The geometric relationship of this sphere to (2^1/2) is as follows:

         There are two different spheres represented in the diagram above. The hemisphere is half of a sphere with a 1.0 m2 surface area; and, the smaller circular X-section represents a sphere with ½ m2 surface area. If the larger sphere divides its surface into two new spheres the lineal measures (radius, etc.) will be reduced by (2^1/2)/2; the smaller sphere is one of these two new spheres. Also, excess volume must be “ejected” in the amount of two tetrahedrons; one of these is represented in the diagram. The surface area of this tetrahedron is the same as that surface “ejected” when we combined the volumes of the two (golden) one surface unit spheres into one. Geometry accounts for these changes in both surface and volume with this “transit-tetrahedron”, the name I came to call it in my book The Geometry of Form.

         Now, here is something about this transitional tetrahedron (its’ formal name) that will tie together in one system both the cubic meter and cubic foot; as well as the troy ounce and its derivatives; and, America’s fractional silver coins. This occurs within the natural element named gold.

         The volume of this golden transit-tetrahedron is .01370203… m3. But this is also equal in volume to .388841339… bushel. And 1/20th of this quantity is .0194420670… which is quite astounding since it is also the illuminati’s geometric derivation of the pint dry measure, the base unit of the bushel (64 of these pints equal a Winchester Bushel). A later chapter dealing with units of volume shows that this pint dry measure came from dividing a special portion (.0940…) of a cubic foot; and the 2.0 ton golden sphere, with the 1.0 m2 surface area, encompasses (.0940…) of a cubic meter.

.388841339… / 20 = .0194420670…

 .0194420670…   X 1.0 cu. ft. = 33.59589… cu. in.

 1.0 pint dry = 33.60031250… cu. in.

          The troy ounce is solidly represented in the various ways of expressing this tetrahedron’s unique volume. First as was mentioned earlier, this volume in pure gold weighs 8500 troy ounces and is the weight needed to “complete” the 3.0-ton cuboid made with 27 mg. cubets. And its’ volume, this time expressed in gallons dry, is 3.11064… and of course this is a power of the 31.1034… grams in a troy ounce. Now a gallon dry, being half a peck, makes this tetrahedron’s volume 1.55533… peck, and this quantity is also the weight of one pence in grams (a pence being 1/20th a troy ounce). When this volume is further broken down into smaller dry measure increments it is found to be the equivalent of 12.442703… quarts dry; or, 24.885633… pints dry. Between 1853 and 1873 these were the weights in grams of America’s fractional silver dollar (24.882781…) and half-dollar (12.441390…).

         It is essential that the reader understand the following: the geometry explaining the surface and volume transformations has nothing to do with any specific weight. The weight applies to the “named” substance occupying the volume and will vary in a direct relationship to its density. Consequently, of all the natural elements GOLD is the ONLY one that can be modeled in commensurate “human” measures in the forms illustrated above. I ask the reader, how can all of this be attributed in any way to “coincidence”?