**The Occult’s Secret Chosen One**

This system begins with *an ideal “unit” of weight*. It is in the *form* of a cube, and this cube weighs 1 “unit”. Until we “name” the unit, the cube has no specific *weight* or *volume* (except for that relating to later *quantitative constructs* as the system develops). Now, this is not the time to explain *why* the illuminati chose this specific geometry to model their system, but for clarity it is important to first actually see how the system was formed and how perfectly it functions.

Next, 27 of these *units* are assembled into one single cube, and then this new cube (as one single unit) is further sub-divided into 1000 mini cubes. Each of these “cubets” has a volume equal to .027 unit. The photo below shows the 1 unit cube; 27 assembled together as a single cube; this cube divided into a thousand mini-cubes; and, the single *cubet* itself.

Up until this point none of these cubes have any *size* or any *weight*. We only know their *relative* volumes. But once we “name” the unit, (in this example) it becomes a *weight*. Then we have could have a *pound*, an *ounce*, a *gram*, a *grain*; some agreed upon weight, with an agreed upon name, in the form of a cube. And until we assign some actual *substance* to the cubes, they still won’t have any meaningful *size*. For purposes of building the system, only the named weight unit is required. The “gram” was the name the illuminati chose and assigned to the beginning cube, and to each one of the 27 assembled together. So now it can be said that any one of the 1000 cubets must weigh .027 gram, or ** 27 milligrams**.

**HUMANITY’S TWO OUNCES**

Using these 27 milligram cubes, and both *perfect* and *perfectly-imperfect* rectilinear geometric constructs, over time they devised the systems of weights and measures for all of humanity. Among the first of their works was the *Troy Ounce* of 480 grains. Many centuries later, they imposed on humanity another 437.5 grain *Avoirdupois Ounce*. Some reading this are probably aware of the blatant contradiction in the above narrative since *history* tells us “grains”, and both ounces built from grains, had been in use long before the French Revolution and the “invention” of the new “gram” unit during the bloodbaths and beheadings. Yet, despite this historical record, I contend that knowledge of a unit we now know as a “gram” *had been well known* to the ancient “illuminati”. I can say this with some confidence because, as we can clearly see from the modeling, these two “quantities” are intimately related. In fact, they even share a single *common geometric core*.

Depicted in the photo at left are both the Troy and Avoirdupois ounces. They are modeled by *perfectly complete rectilinear cuboids* comprised of 27 milligram cubets. Historically they have no known special relationship to one another. Allegedly these weights were arrived at by thoroughly arbitrary and subjective processes such as *feeling like the “right” amount*, or *by decree* of some king. In the picture, one can clearly see that *both ounces share a “common core”*, which is define by the white cubes in both columns.

Now let’s look at each of the two ounce columns and associated math. The Troy ounce on the left has 6 cubes by 8 cubes forming its base, and is 24 cubes high. There are in all 1152 cubes (6 X 8 X 24), each with a weight of .027 gram.

**1152 X .027****gram = 31.104****grams**

The number of grams in a Troy ounce was finally determined *by agreement* among the nations of the world *after* reaching *an agre*ement on how many *grains* are contained in one *gram*: 15.43235835 grains. Therefore, the ancient Troy ounce of exactly 480 grains contains 480grains / 15.43235835grains/gram = 31.1034768grams. This compares to the *ideal* modeled weight in grams as:

** 31.1034768 / 31.104 = 0.99998**3179…

By comparison, the column modeling the Avoirdupois ounce (on the right in the photo) has a base measuring 6 cubes by 7 cubes and is 25 cubes high. There are 1050 cubes in all, each with a weight of .027 gram:

**1050 X .027****gram = 28.35****g**

Again, just like with the Troy ounce above, The Avoirdupois ounce of exactly 437.5 grains contains 437.5grains / 15.43235835grains/gram = 28.349523125grams. And this compares to the *ideal* modeled weight in grams as:

**28.349523125 / 28.35 = 0.99998**3179…

Nobody can deny the elegant beauty and simplicity, let alone the *accuracy* of these models. If one begins with their common core of white cubes alone, it is easy to see that one need only add one complete course to one of this cuboids faces to get one of the ounces. If instead, another one of its faces is covered with one complete layer, then *like magic*, there is the other ounce. And as for the “core” of 1008 of these cubets, and its 420 grain weight; much more will be said about this special quantity later.

Now for any skeptics who would attribute this all to “coincidence”, keep in mind that already there is more than just one of these *coincidences*. For example, it might be coincidence if both ounces just happened to be capable of perfectly complete cuboid modeling by the same little cubet, but resulted in two unrelated cuboid models. But that in reality they are opposite face modifications of the same “core” column of cubets; and that both “historically unrelated” ounces mirror their respective modeled counter-part weight-measures to *the same* *identical degree* *of perfection:* 0.999983179…; and if in 1588 Queen Elizabeth had *not* “coincidentally” increased the weight of the avoirdupois pound from 6992 to exactly 7000 grains, then posterity would have been *spared* that awkward ½ grain in their present 437**.5** grain ounce and would make all of the previously demonstrated modeling impossible and simply obliviate any notion that these quantities are *purposely related through geometry*. Forget about *coincidence* in this case.

And surely any further notion of coincidence will be laid to rest once this following question is answered: *why did they purposely choose 12 ounces for the Troy pound, and 16 ounces for the Avoirdupois pound*? My research comes up empty for any reasonable *historical* answer. But I believe I have found the real reason *in the geometry* that is revealed when we arrange these respective “ounce” quantities of 27 milligram cubes *in some particular fashion*. Let’s have a look at *why* these quantities of 12 and 16 ounces were *really* “chosen”.

**Why 12 Ounces in A Pound Troy ****And 16 Ounces in an Avoirdupois Pound**

In the photo below is a perfect cube made from 13,824 “cubets”. There are 24 cubets per edge. Each little cubet weighs .027 gram. Therefore, the total weight of this cube in grams is

**13,824 X .027****gram**** = 373.248****grams**** **

In “grains”, 373.248 grams equals 5760.09688… grains (note 373.248grams X 15.43235835grains/gram = 5760.09688…grains), and there are 5760 grains in a pound Troy:

**5760 / 5760.09688… = 0.99998**3179…

The “perfect” cube in the photo is one pound Troy. The 12 columns delineated by the red lines are 12 of the Troy ounce columns of 1152 cubets shown on the left in the previous photo. *This complete and perfect geometry is why there are12 ounces in one pound Troy.*

The geometry of the Avoirdupois pound of 16 (437.5 *grain*) ounces is also modeled on the cube, although a little differently. In the photograph below each of the two “cuboids” depicted equal ½ pound, which is 3,500 grains (there being 7000 grains in 1 pound AV.). These are cube-*oids *and not *cubes* because each of the two perfect cubes (depicted by the white 27mg cubes in the photograph) has *1 additional complete layer* of sub-cubes added to one face. In the photo these two layers are highlighted in red.

Each of the two perfect *cubical* assemblages is a cube with 20 cubets per edge. With the additional course of red cubets, each *cuboid* then measures 20 X 20 X 21 cubets/edge, or 8,400, and weigh ½ pound AV since

** 8,400 X (.027****gram) = 226.8****grams, **

**and**

**3500****grains / ****15.43235835****grains/gram**** = 226.796185****grams**

**and**

**226.796185****grams**** / 226.8****grams = 0.99998**3179…

Thus the Avoirdupois *pound* is seen to perfectly model the geometry pictured above *exactly to the same* (better than ten-thousandth) number place as the supposedly unrelated *centuries older* Troy *pound* when it too is modeled by the same 27mg cubets.

Later in this manuscript, the modern “gallon” unit of volume measure, which is based on the *cubic inch*, will be shown to have identical modeling properties.

**Additional Models of the Troy and Avoirdupois Ounces**

This is a very simple model to imagine: two-thirds, or .**666…** of a perfect cube which itself is comprised of 27mg *cubets*. It has 12 of these cubets per/edge, and 1728 form the complete cube. Two-thirds of 1728 is 1152 cubets. A few pages back is pictured 1152 cubets stacked as a 6 X 8 X 24 cuboid column identified as one Troy ounce. Pictured above is the 12 X 12 X 8 cuboid which is an alternative model of this 480 grain unit of measure. Again, here is one complete course of red cubets atop 1008 white cubet. And again, a few pages back, 1008 cubets was shown to be the common core of *both* ounce columns, and would become the future 420 grain U.S. Trade Dollar. Divide in half this core column (of 24 courses, each with 6 X 7 cubets/edge) and re-arrange the two halves into the white cubet portion depicted in the above photo. Then, almost like magic, *by adding one perfectly complete layer* to the appropriate face of this re-arranged ounce column and the Troy ounce is again produced.

The cuboid in the next picture consists of 1050 cubets weighing 27mg each. They assemble in a 7, 10, and 15 per/edge cuboid. Again, 1050 cubets were previously shown to weigh one Avoirdupois ounce of 437.5 grains.

***

In this case, the one complete course of red cubets leaves 900 white cubets beneath. *This is significant* as it is this assemblage of white cubets that unifies * the Avoirdupois ounce and the American silver dollar coin* in the same way that the 420 grains of the Trade Dollar as a tall slender column unified this same A.V. ounce with the Troy ounce. Let’s have a look at the geometry just described.

**The Silver Dollar, the Avoirdupois Ounce,**

**And the Accounting System**

**Based On the 27 Milligram Cubet**

** ** History clearly tells us that there is no “special” relationship between the gross weight of the silver dollar coin and the Avoirdupois ounce. According to the historians, both measures were arrived at arbitrarily and subjectively. *This is simply untrue*. Its not that the historians have been lying to us, the world’s peoples, but that *they* (the historians) have been lied to through out the ages. As it is often said today with all things *computer *related, “garbage in, garbage out”. As for history, I’m convinced that most of what is really important is never disclosed, or it’s simply covered-up with a lie. Most of history, because of what I now know, is certainly corrupted “garbage” designed for, and fed to the masses of unaware people. Most of history is beyond repair.

The same group of unseen deceivers assured the implementation of these *specific* weights. In so doing, they were literally *enshrining* an occult *science* into the emerging world-systems of weights and measures, and especially into the new American coinage. For into this coinage, using geometry, they would (in *their* minds) imbue* magic* and *power*. In this way, beginning with the 1792 Coinage Act they created a system of coinage that (they believed) would gain precedence over all other monetary systems.

The photograph below shows the 900 white cubets (highlighted in the previous picture of the Avoirdupois ounce) assembled as a single cuboid. It is situated between the 437.5 grain A.V. Oz. to the left and a weight of **412.5** grains to the right. Of course, **412.5** grains is the weight of the American silver dollar

This picture clearly shows how *the same cuboid*, by adding one complete additional layer of 27mg cubets to the appropriate face, becomes in the one case an Avoirdupois ounce; and in the other case, the silver dollar’s **412.5** grain weight measure.

These simple *form*al transformations conclusively prove that there is an inseparable geometric/mathematical affinity between these two quantitative measures that is inherently built into this *natural system of geometry*. They simply are not *arbitrary* quantities to geometry and mathematics, nor were they *arbitrary* to the group of illuminati who steered their acceptance through the various legislative bodies over the course of time.

Further proof, if any more be needed, that the *Avoirdupois ounce* and a weight of *412.5** grains* are in fact “*geometric siblings*”can be found in the simple *line*, which gives birth to both quantities. Here’s how it works.

In the photograph below are two polyhedrons. Both are made from the *same* line in

the sense that *the sum of the edgelengths* of each form are equal. In fact, in the eyes of geometry the two forms are *1 ^{st} dimensional equivalents*. Now if the cube is made out of one Avoirdupois ounce of American coinage silver, 437.5 grains, then the weight of the tetrahedron

*made from the same metal*will have to be 412.47895… grains. And this

*is*

**412.5**grains to better than

**99.99%**perfect commensuration.

**412.47895… /** **437.5 = .9999489…**

This is simply the way geometry *itself* inherently operates. This is a view into *the* *geometry of form*. This is not taught to the peoples of the world for a reason. It is not taught, because to do so would expose an unimaginable level of deception, not only with respect to our weights and measures, but to our understanding of science and history as well. Remember just as E = mc^{2 }, *knowledge = power*.

### **Modeling the Silver Dollar Coin**

**Using the 27mg System**

There is more than one way to model **412.5** grains, in a perfect and complete geometric form, using nothing but 27 milligram cubets. The photo above is one manner of such modeling. The white cubets is the *common core* shared by the Avoirdupois ounce, as was just illustrated two photos back. But there is another modeling form that was *specifically chosen* for the American silver dollar. In this assemblage the cubets arrange in 10 layers, with 99 in each layer. The photo at left below illustrates this modeling.

They chose this modeling for at least two reasons: the first is that the perfect cuboidal assemblage of white cubets beneath the red (891 of them) weighs **371.25** grains. * This is the exact amount of pure silver in the silver dollar coin*. The remaining layer of red cubets (99 of them) weighs

**41.25**grains and

*. Look at the next photograph below. What you are looking at is the*

__is the amount of copper alloy in the coin__*recipe*, or

*formula*for .900 American “coinage silver”.

Both of these metal’s *quantities* (**371.25** and **41.25**) are very special to *the geometry of form.* So too is the 9/10 ratio also an integral part of geometry’s structure. This is clearly demonstrated by the following very simple forms. They reveal *essential structuring* which goes back to the very foundation of geometry. This “structuring” is based on *geometry’s preferred* forms for the three *powers* of the fundamental unit *in a three dimensional space frame*.

The graphic to the right depicts the view looking at the leading edge of four tetrahedrons; 1 large red, and 3 smaller blue tetrahedrons. Now for *scale*, imagine a single line equal to 1.0 unit in length having been reconfigured into the six edges of a blue tetrahedron. That means each of the blue tetrahedrons is considered to be * 1.0 unit of length in the form of a tetrahedron’s edges*. In this way the one-dimensional line is transformed into a three-dimensional form.

The edges of the red tetrahedron are formed from three of these 1.0 unit-length lines. As we see in the graphic, the combined height of three “unit length” lines in the form of three separate tetrahedrons’ edges equals the same exact height as the same three lines *together* when forming the edges of a single tetrahedron. Again, this is a geometric “law, in a manner of speaking.

Now, imagine a *square *that is the same height as the tetrahedrons. If this square is one of the six faces of a cube, then that cube measures * 1.0 surface unit (or square unit) in the form of a cube’s surface*. With all due respect to Euclid’s

*units*as line and square,

*the geometry of form*prefers the tetrahedron and cube for 1

^{st}and 2

^{nd}dimensional accounting purposes in a three-dimensional space frame.

Obviously “geometry” appreciates this commensuration of fundamental *quantity* and *form*. But how does this relate to the silver dollar coin? Here’s the answer: if we change the scale and make the red tetrahedron **371.25** grains of pure silver, then each of the blue tetrahedrons are 13.75 grains of pure copper, or **41.25** grains all together. If you combine these four metallic tetrahedrons together what you get is the *exact* amount of the metal *alloy* for one silver dollar coin. Once again, like the cuboid in the previous photograph, this is the recipe for America’s .900 COIN SILVER. It is inherent to *the geometry of form*.

**The Silver Dollar and the $10 Gold Eagle**

The 1792 Coinage Act created a $10 gold coin. It is called the “Eagle” and it weighs **270** grains. America’s first gold coins are 22 karat which is to say that these gold coins are 11/12^{ths }pure. This means that the Eagle contains exactly **247.5** grains of pure gold.

**11(270****grains**** / 12) = 247.5 ****grains**

** **The silver dollar and *eagle *are depicted in the photo to the left The silver coins are 9/10^{ths} pure silver. Once again, this modeling reveals the same visual and geometric design themes at work here in the1790’s and early 1800’s as with all of the other key weight examples shown thus far going all the way back to the nearly *ancient* troy ounce. And just as the layer of red cubets indicates the 9/10 alloy ratio of the silver coin’s cuboid (depicted in the foreground), so too does the *complete* layer of red cubets indicate the 11/12 alloy content of the gold coin’s cuboid nestled behind.

It is clear from the picture that the *cores* of these two coins are intimately related. The white cubets, which depict each of their respective pure metal contents, are these two cores. In 1792 *it was claimed* that the exchange ratio between gold and silver globally was 1:15, which translates to 0.0**666**…, a power of 2/3. One grain of gold would buy you fifteen grains of silver.

Now a $1 gold coin would theoretically weigh 27 grains. If modeled by 27mg cubets, it would have one tenth the number and be much smaller than the cuboid in the photograph. That’s why when increased to a $10 coin, its core becomes two-thirds, or .**666**… the silver dollar’s core. In this manner *their geometry* is replicated.

But this is only where the unique properties of this weight measure chosen for the Eagle coin begins. Remember, at the heart of this system of weight measures are the *grain* and the *gram*. And as we’ll see next with the **270** grain Eagle coin and its** 648** cubets that comprise its perfectly complete cuboidial form, it literally mirrors the *micro-modeling* that links the gram and grain * from the very starting point* in that one greater

*occult system*from which

*both*were derived. Have a look.

**Original American Eagle Coin ****Models The “Grain” ****In The System Which **

**Gave ****Birth ****to the Weight Units ****Known as the “Gram” and the “Grain”**

Another of the many reasons the weight of **270** grains was chosen for the $10 gold Eagle can be seen, once again, in its *modeling geometry*. In the photograph above we see a perfect cube assembled from 27mg cubets, with 9 cubets/edge. Remove one complete layer from any face (in red) leaves the white “cuboid” portion. It is comprised of 648 cubets: 9 X 9 X 8 = 648. Since they each weigh 27mg the cuboid weighs 17.496 *grams*. At 15.43235…grains/gram it also weighs **270**.00454.. *grains*, and:

**270****grains**** / 270.00****454… grains ****= .9999****8317****…**

But probably even more significant is the Eagle’s ** form**al relationship to the

*grain*itself when viewed in the modeling system from which was

*also*spawned the unit that (today) we know as the

*gram*. Remember, an

*ounce*measure is a natural “unit” only in systems based on the grain and pound. On the other hand, the gram’s first natural aggregated measure is the

*kilogram*, and it sub-divides into

*milligrams*. This is the

*traditional*view.

Here is the *occulted* view. Start with a perfect cube which itself is comprised of 1000 mini-cubes, i.e. 10/edge. Quanta-size its volume as = 0.1. Therefore, ten of these cubes together in one system gives that system a volume = 1.0. Now introduce a second cube comprised of the same mini-cubes but with only 9/edge; then, *remove one complete layer* of mini-cubes. Though it is a diffent size, this remaining cuboid is the *same* cuboid in form and quantity that models the Eagle coin depicted at left. The (as yet *sizeless*) forms just described in this paragraph are depicted in the photograph below at right.

Now it is time to assign *scale* to these forms. Since, by previous definition, the ten cubes in the background total volume **1**.0, or more descriptively, “10/10 volumetric unit”; then by comparison, the lone cuboid’s volume must be 0.0**648**. But there is still no *scale* until a *name* is assigned to that **1**.0 unit. The Illuminati called it their “Gram”, since it is in fact the *grampa* of all *weight* measures that followed. And just how close to the perfection of these *geometric ideals* do the measures of today actually conform? As we can see below, much too close for coincidence.

**1.0 / 0.0648 = 15.432098… / 1.0**

** ****and, there is 15.43235835…grains/1.0 gram**

** ****15.432098… / 15.432358… = 0.99998****3179…**

** **** **In fact, to demonstrate this is not just some cute foible (that we find the *image* of the grain itself replicated in the Eagle’s modeling) I will at this point indulge the reader with a glimpse of just where this narrative will soon take us. So with out actually going down this “fork in the road” just yet, we will pause momentarily and take a peak at where it begins.

**(A Momentary Pause at a Fork in the Road)**

** ** Thus far we have been traveling a pathway that shows us where humanities measures of *weight* have originated. There we have seen that quantities specific to American gold and silver coinage such as **371.25**, **412.5**, **270**, and **247.5** to be quantities inherent to “geometry” itself. This momentary detour takes us to where the measures of *length* originated, i.e. the present world’s two systems based on the *millimeter* (mm) and the *inchmeasure* (im). Get out your calculator because you probably will find this hard to believe.

Of course, we are reminded that history tells us there is no *intentionally* designed relationship between these two systems, the one very old and the other relatively new; except, of course, for *the ratio* calculated (after the fact) for converting the one into the other. Over time it was determined that the two systems would be commensurate at a fundamental unit of length (called an “inch”), and that it contained exactly 25.4 *millimeters* or exactly 32 *inchmeasures*.

**25.4 / 32 = 0.79375**

** **Multiplying the number of inches by 25.4 gives the number of millimeters; dividing the number of millimeters by 25.4 gives the number of inches. The number 0.79375 is telling us that one *inchmeasure* (1/32) is only 0.79375 the length of one *millimeter*. This is *overtly* what we end up with. But *covertly* there is something else altogether going on.

To the ancient illuminati who first discovered *the geometry of form*, and have kept it an *occulted* secret ever since, the two measuring systems relate as:

**(2.0 ****― 0.4125) / 2.0 = 0.79375**

** ** By now it must be pretty obvious that there *is something* going on here. The single quantity distinguishing the two systems of *length* measures, 0.**4125,** is the exact quantity essential to understanding the two systems of *weight* measures. In fact, the entire system that I have come to call the “*inchmeasure*” is itself based upon this **4125** *quantifier*, which we will soon see is inextractibly woven into its very fabric. For example, overtly a .**4125** portion of *one-foot* is 4.95 inches; and, 49.5 inches is **4.125** feet. Also, 4.95 inches is twice **2.475** inches which mirrors the **247.5** grains of pure gold in the $10 Eagle coin.

As this manuscript progresses, the reader will come to see that *America**’s entire system of public land measure*, and much of the world’s as well, from the mile to the acre, is literally based on these quantities of **412.5**, **371.25**, **270**, **247.5**, and their derivatives. And remember, each of these *quantities* have been shown to be among the essential measures defining America’s gold and silver coinage.

**The Geometric Origin of**

**THE “TON”**

### And It’s Imprint In* Natural Structure*

** ** To the general public a “ton” is simply **2000** *pounds*. These are *avoirdupois* *pounds*, and since each *pound* equals **7000** *grains* a ton is also **14,000,000** *grains*.

It could easily be concluded that this ton measure arose as the result of needing a “convenient” unit for large aggregations of pounds. And that they designed this measure in *base*–*ten* could be viewed as just another added advantage of convenience. If this is in fact the case, then we really should *not* expect anything of significance to be found by looking any deeper into this particular measure of weight. Let’s have a look anyway.

We are aware that the “**27** *milligram* cubet” has already been exposed as being the *base* *unit* of the *illuminati* *designed* systems of *weight* measures thus far studied. Maybe by modeling this *ton* measure with these cubets we can unveil even more mysteries.

In this **27*** milligram system of weight measures* a single “cubet” weighs **27** mg.; but, it also *equally* weighs **.41667**3676… *grain* (which can also be expressed as **1 / 2.4** grain to better than .**9999** fine). In this system, **14,000,000** grains, modeled in cubical **.41667**3676… grain units, requires **33,600,000** cubets. The previous sketch reproduced here from my notes reveals the first of many surprises regarding the “ton”.

Is it coincidence or by design? A *perfectly* *complete* cuboid can be assembled from **33,600,000** cubets? Moreover, the proportions of this cuboid are the *exact same* quantities defining the *number of grains in each of our “ounce” units*. Thus in **27** *mg*. cubets, a 1.0 ton cuboid will measure precisely **160** layers of cubets with each layer **480** cubets by **437.5**. Each layer weighs **12.5** pounds. (Note: **437.5** grains equals one *avoirdupois* oz., and **480** grains is one *troy* oz.)

After noting the above, my next thought was the realization that 160 is a third of **480**. I could stack two more cuboids atop the one in the sketch and have an even more perfect and complete cuboid. This **3**-ton assemblage measures **480** X **480** X **437.5** cubets and is depicted in the following sketch.

There was something else I noticed that seemed to make this specific measure of weight *significant* and *unique* with respect to both systems based on the *grain*. . . much more so than the single ton, or two tons.

1 Ton = 32,000 *Av. oz.s* or 29,166.666… *Troy oz.s*

2 Tons = 64,000 *Av. oz.s* or 58,333.333… *Troy oz.s*

**3** Tons = **96,000** *Av. oz.s* or **87,500**. . . *Troy oz.s*

Whereas 1 and 2 tons create irrational numbers of troy ounces, **3** tons creates *whole unit amounts of both ounces*. In fact,

**3**tons can be seen as equaling:

(**2000** X **480**) *Avoirdupois oz.s*, or:

(**2000** X **437.5**) *Troy oz.s*

It is clear to see from the data above that **3*** tons perfectly unites the two systems of weight measures based on the grain*. Aside from the *grain* itself, these two systems have no known historic relationship to one another, yet they clearly are intimately related.

Again, referencing the drawing immediately above, one can’t help but notice that in the **27** *mg*. cubet system of weight measures, **3** tons model as an *incomplete* cube. The *complete* cube is an *ideal* form to which the *actual* assemblage only approaches; and it measures **480** cubets on *all* its edges. And (**480**)^{3} equals **110,592,000** cubets compared to the **100,800,000** cubets comprising **3** tons. Thus, the ideally *completed* cube compares to the **3.0 **ton cuboid assemblage as:

100,800,000 / 110,592,000 = .91145833… , and

1 *A.V. oz*. / 1 *Troy oz*. = .91145833…

showing that **3** tons is to an *avoirdupois* *ounce*, as **3** tons *plus* **582.86694**… *pounds* is to the *troy* *ounce*. This **582.86694**… *pounds* is the amount required to *complete* the cube (Note: 9,792,000 cubets is the difference between the two assemblages; multiplied by .027 gram cubet = 264,384 grams; times 15.4323…grains/gram = 4,080,068.63…grains; divided by 7000 grains/pound = 582.86694… pounds).

Shortly, we will return to this seemingly odd quantity and see the important role it plays in our understanding geometry’s influence not only on *the* *measures* *of man*, but *nature’s* as well.

**The ****Ton**

** The Meter Measure, and**

**The Element Pure Gold**

** **** **Imagine a *cubic* *meter* of pure gold. Each of this cube’s six square faces measures exactly **1.0** *square* *meter* and each of its twelve edges are **1.0** *meter* long. According to *All* *Measures* .*com* (a research resource site for engineers and scientist), and corroborated by other sources, pure *gold* weighs **19,300** *kilograms* per *cubic meter*.

This time imagine 1.0 *ton* of pure gold. Unless you know something about gold, this is harder to do than imagining a *cubic meter* of . . . anything. A *cubic* *meter* of any substance is always the same size. But it is helpful to our imaginations when we find that **1.0** *ton* of gold is equal *in volume* to:

.**0470**0518… cubic *meter*

** 1.333**9… *bushel*

**47.0**05… *liters*

**99.33**4… *pints*

All of these quantities were familiar to me as they are found throughout *the geometry of form*. It seemed odd to me seeing them here together, not only as man’s measures, but applying to gold as well. These units seem to be *discrete*, in the sense that they are *distinct* or clearly *defined *with very little residual. **1.0** ton of gold is equal in volume to **4/3** *bushel* to a very, very close tolerance. Likewise, it is the volume of **47** *liters*, as well as **1/3** of **298** pints. The *actual* measures correspond to their whole number *ideals* to better than .**999** fine. It certainly appears there is something going on here that is inexplicable in light of our current understanding of history and science. *Why is gold so neatly accommodating to man’s arbitrary measures?*

Of the four equivalent measures above, it was the **1.0** ton of gold’s *volume* as a portion of a *cubic* *meter* that really caught my attention (of course the *liter* follows from the *meter*). This is a very special *volume* quantity in transformational geometry. This is because when **1.0** *surface* *unit,* in the form of a sphere’s surface, divides its *volume* into two new spheres, each of the new spheres will have a volume of .**0470**15799… cubic “unit” (by whatever name is assigned to that unit). Obviously, this means that the volume of the original sphere before dividing is **.0940**31597… and that the *area* of its surface is **1.0** *square* *unit*.

To me this is amazing, because it means that if **2.0** tons of gold has a *volume* equal to .**0940**103… *cubic* *meter*. . . then this *precise* amount of gold, if molded into a perfect sphere, will *create* a surface area equal to .**9998**49… *square* *meter*. (Note: the length of a *meter* is 39.37007874 *inches* exact, and a square meter equals 1550.0031 square inches.)

Here now is the model I saw coming into focus. We started with a cube and designated it our system’s *unit*. Its’ edge is **1.0 ***unit* long, and each square face plane is **1.0** *square* *unit*. By naming this unit a “*meter*” we introduced real-world *scale* on to the cube. If now we create a sphere with a surface area equal to any face plane of the cubic meter, this sphere’s surface area will equal exactly **1.0** *square* *meter*. Its *volume* is now **.0940**31597… *cubic* *meter*. If this volume is pure gold it weighs **4000**.9740… *pounds*; or equally **2.000**45… *tons*.

The geometry tells us that the “ton” measure is the *unit* with respect to *weight*. And that it is the “meter-measure” that is the natural unit of *length*, *area*, and *volume*. These supposedly *unrelated* units, the *meter* and its derivatives and the *grain*–*based* ton and its derivatives, become integrated into *one* *commensurate* *system* ultimately based on a *unit of substance*: __pure gold__.

There is another geometric model that applies* only *to **3.0** *tons* of gold. This model is “complete”, and more elegant than the cuboid made earlier from the 27 milligram cubets (which models the **3.0** ton measure of *any* substance). In “The Geometry of Form” it is called “the cylinder of maximum volume” and is a *geometric* *ideal* capturing the most volume with the least surface given the *cylindrical* form. Now we’ve already seen that **2.0** tons of gold contained within a sphere has a surface measure of **1.0 ***square* *meter*. If this sphere is then encapsulated within the smallest cylinder in which it will fit, like a ball in a tin can, the height and the diameter of the cylinder are equal to the diameter of the golden sphere within (which is bluish-green in the illustration below). In geometry, a cylinder of this proportion is *the cylinder of maximum volume*. When the surface area of the cylinder holding the sphere of gold is calculated, its side area is found to be **1.0** square *meter*; and each of the two circular ends measure **.25** square *meter*.

So far this model has two forms: the **2.0** ton golden sphere and the enclosing cylinder. But the negative space inside, the *void* surrounding the enclosed sphere, is a third form. And if instead of *void* this space is filled with pure gold . . . it will weigh **1.0** ton. Now we are modeling **3.0** *tons* of gold within a surface area of **1.5** square *meters*.

With two different geometric forms, and the *exact* area measures of **1.0 **and **1.5 **square *meters*, **2.0 ***tons* and **3.0** *tons* of pure gold can be packaged *with near mathematical perfection*. To be exact, **3.000**6776… tons of *pure gold* is contained within the *cylinder of maximum volume* form if its *surface* *area* measures __exactly__ **1.5** square *meters*.

Let’s now revisit the *cuboid* and *cube* that earlier in this chapter were constructed from the **27** *milligram* cubets. The cuboid, which is the nearly *complete* cube, models **3.0** tons and contains **100,800,000 **cubets (**480** by **480** by **437.5** cubets). The completed cube (**480** by **480** by **480** cubets) contains 9,792,000 additional cubets adding **582.8669**… *pounds* to the cuboid’s initial **3.0** tons. How this quantity models and interacts with the fundamental geometric units distilled thus far *from the properties of gold*, again is simply amazing. Take a look . . . in *your mind*, of course, and follow along as I try to describe what I am seeing.

First of all, by now we should know from all of what has transpired in the previous chapters, that geometry is trying to tell us “something” with this *difference* *quantity*. First, let’s look at it as the *weight* we know it to be; and that is **582.8669**… *pounds* (regardless of what substance). But this is also 4,080,068.630… *grains*:

4,080,068.63… *grains* / **480** *grains* = **8,500**.1429… troy *oz*

This equation resolves a very non-descript number of pounds into a near perfectly discrete number of *troy* ounces. And this is from a number that was deduced from modeling a **3.0**-ton quantity using the *illuminati’s* **27** *milligram* system of weight measures.

So far we have been working with a *weight* of **582.866**…. pounds. Before we can investigate a *size*, a physical *volume*, this *weight* must be assigned a *named* substance. Of course, for purposes here, *gold* is the name of the substance weighing **582.866**…. pounds, or equally **8,500** troy ounces. Now we can calculate its *volume*.

First we convert the number of *pounds* into *grains* by multiplying by **7000**. This quantity is divided by 15.43235…, the number of grains per gram, giving us the number of grams in **582.866**… pounds: *exactly* **264,384** grams. Divide this quantity by **1000** and we have the number of *kilograms*: **264.384**. Since this is the weight of a specific quantity of gold, and since gold weighs 19,300 kilograms per cubic meter, by dividing

**264.384 kg. / 19,300 kg./m ^{3 }= .01369**8653…

**m**

^{3}we arrive at the physical size of this **582.866**… pound unit of gold. In “round numbers”, so to speak, it is .**01370** *cubic* *meter*.

This number defines a *volume* quantity of gold. At this point, it is *without* any specific form. But to *geometry*, it can be the *volume* of a geometric form that is *essential* for maintaining *surface* and *volume* accountability as a result of *geometric* *transformations*. One such typical transformation is *fusing* the volumes of two units into one unit. Because of the more efficient “packaging” (in a single form), less *surface* *area* is required to contain a given *volume*. Now, let’s look at the **2.0** *ton* sphere of gold, with its **1.0** square *meter* surface area, and see what happens when it fuses its *volume* with another sphere’s volume *identical* to itself.

Each of these spherical volumes of gold is .**0940**…*cubic* *meter*; so the volume of the new (**4.0** ton) sphere of gold is **.1880**… *cubic* *meter*. Its surface area is **1.5874010**… *square* *meters*, and is equally expressed as [(**4.0**)^{1/3} m^{2}]. This surface is .**4125**9894… *square* *meter* *less* than the **2.0** *square* *meters* originally containing the **4.0** tons of gold in the form of the two *separate* spheres. Out of all the *forms* to choose from, geometry configures this “excess surface area” into the *form* of a regular *tetrahedron’s* surface. The *volume* contained inside this *surface* *area* is .**01370**203… *cubic* *meter* (m^{3)}. If this is a unit of pure gold it will weigh:

.01370… m^{3}(19,300 kg/m^{3} ) = 264.44… kg = **583.01**…lbs

Remember that the **3.0** ton cuboid model (made from the 27 milligram cubets and discussed back on page 140) fell shy of being a perfectly completed *ideal* cube And that the volume of this *ideal* cube with **480** cubets/edge was shown to be **3.0** tons, *plus* **582.8669**471… pounds. Now let’s compare this weight (calculated from the system of **27** *mg* cubets) with the weight immediately above derived from the *pure* *geometry* resulting from the fusion of two spheres of pure gold (with their surfaces each perfectly scaled to **1.0** square meter) into a single sphere.

**582.8669**471… pounds / **583.0107**353… pounds = .**999**753…

Before moving on, let’s take an inventory of the *solid gold* geometric forms thus far distilled from *mankind’s* “ton” measure of weight. Our first clue that there was something *special* going on was the *volume* of **1.0** ton in cubic *meters*: .**0470**…m^{3}. It was because of my years researching *the geometry of form* that I immediately recognized this quantity as *one-half the volume of a sphere with a surface area equal to* **1.0 **“unit”. This led to the realization that if **2.0** tons of gold is contained within the surface confines of a sphere having a .**0940**… m^{3} volume, then its *surface* *area* must equal **1.0** m^{2}. Next we found the **3.0**-ton packaging using *the* *cylinder* *of* *maximum* *volume* having a **1.5** m^{2} *surface* *area*.

Slamming two of these **2.0** ton golden spheres together fused their gold into a *single* sphere of **4.0** tons. In this *transformational* *process*, there is an “excess surface” quantity amounting to .**4125**9894… m^{2}.

We now know that if this *surface* *area* is in the form of a regular tetrahedron’s surface it will encompass a volume of .**01370**… m^{3}. And, that *this* volume of pure gold weighs **583**.0107… pounds; which as we previously calculated is also (just coincidentally??) the weight in *pounds* (**582.8**66…) modeling the *difference* *quantity* separating the **3.0** ton cuboid (made from the **27** *milligram* cubets) from its implied *ideal* completed cubic form. In the graphic above, *this* *tetrahedron* sits atop ½ of a **2.0** ton *sphere* of gold.

On the left is the plan view of the (hemi)*sphere* and *tetrahedron*. One cannot help but notice how closely the three tips of the tetrahedron’s base correspond to the circumference of the sphere’s cross-section. This is a *physical* or *formal* commensuration.

The right hand side of the illustration is a frontal view of the tetrahedron atop the **1.0**-ton hemisphere. We also see the X-section of another sphere having its surface area equaling **½** *square* *meter*. Note that its diameter is the height of the tetrahedron; this makes it *physically* *commensurate* to the tetrahedron, just as its’** ½*** m ^{2} surface area* makes it commensurate to the hemisphere’s

**½**

*m*(atop of which it sits). The

^{2}surface area*volume*of this sphere is also imprinted with some interesting geometric constants.

For example, the *cube* of its radius is .00**793**6704… The essence of this quantity is .**79370**0526… which, as we have seen in a previous chapter, is geometry’s inherent constant defining the *lineal* relationships underlying *volume* transformations. Moreover (again, as we have seen earlier) it exposes the “metric/inch” relationship that is at the very heart of geometry itself:

**32** X .**7937**005…mm = **25.398**41.. X **1.0**00..mm = **1.0 “**

**and**

**25.39841…mm / 25.4 mm = .9999**376**…**

Note: There are exactly **25.4** “millimeters” per inch; or **32** “inchmeasures” per inch, and **25.4 / 32 = .7937**5** / 1.0**00

Interestingly, I see *silver* measures in the *volume* of this 2^{nd} generation *golden* sphere. Its’ volume is .03324519… m^{3}; and since it is pure gold, its’ weight is .03324519… X 19,300 kg/m^{3} = 641.632167… kg; or 641,632.167… *grams*. This is also **9,90**1,897.53… in *grains*. In the *illuminati’s* **27** *mg* weight system, **990.**0000 *cubets* weighs **412.5**0693… grains, which is the gross weight of the American *silver* *dollar* coin. We can say that this sphere’s weight is **9,90**0,000 grains to a .**9998**… degree of exactitude. This is the weight of **24,000** *silver* *dollar coins.* If we want to be precise, this sphere is the weight of **24,004.**6… *silver dollar coins.*

Further confirming this inherent relationship between *silver* “coinage measures” and *these* specific weights in *gold* is seen when the same weight is expressed in *troy* ounces: **20,62**8.93780… Once again, this is **20,62**5 troy ounces to a .**9998**… degree of exactitude. This means that two such spheres of gold weigh **4125**0 *troy* *ounces* to this same .**9998**… degree of exactitude.

We can see silver’s coinage measure even when this .03324519… *volume* quantity appears as a *surface* quantity in the form of a *cube.* This cube’s *volume* of .000**4124**45… is a .**9998**66… facsimile of the *silver* *dollar* *coin’s* quantity of **412.5** grains. This is not coincidence; this is how *the* *geometry* *of* *form* is “quanta-sized”.

Now, there *is* also a geometric reason *not to be surprised* that the weight in *pounds* of this golden sphere with a surface area measuring **½ m ^{2}** is (to a .

**9999**489… degree of perfection)

**1000**times

*the square root of two*units (

**2^**); which is

^{1/2}**1,414**.21… pounds;

**1,414**.55… pounds is its’

*precise*weight. The

*geometric*

*relationship*of this sphere to (

**2^**) is as follows:

^{1/2} There are two different spheres represented in the diagram above. The hemisphere is half of a sphere with a **1.0 m ^{2}** surface area; and, the smaller circular X-section represents a sphere with

**½ m**surface area.

^{2}*If the larger sphere divides its*(

__surface__into two new spheres the lineal measures (radius, etc.) will be reduced by**2^**)

^{1/2}**/2**; the smaller sphere is one of these two new spheres. Also,

*The surface area of this tetrahedron is the same as that surface “ejected” when we combined the volumes of the two (golden) one surface unit spheres into one. Geometry accounts for these changes in both*

__excess volume__must be “ejected” in the amount of two tetrahedrons; one of these is represented in the diagram.*surface*and

*volume*with this “transit-tetrahedron”, the name I came to call it in my book

*The Geometry of Form*.

Now, here is something about this *transitional* *tetrahedron* (its’ *formal* name) that will tie together in one system *both* the cubic *meter* and cubic *foot*; as well as the *troy* *ounce* and its derivatives; and, *America**’s* *fractional* *silver* *coins*. This occurs within the natural element named *gold. *

The *volume* of this golden *transit-tetrahedron* is .**01370**203… m^{3}. But this is also equal in *volume* to .**38884**1339… *bushel*. And **1/20**^{th} of this quantity is .**019442**0670… which is quite astounding since it is also the *illuminati’s* geometric derivation of the *pint* *dry* measure, the base unit of the *bushel* (64 of these *pints *equal a *Winchester* *Bushel*). A later chapter dealing with units of *volume* shows that this *pint* *dry* measure came from *dividing* a special portion (**.0940**…) of a cubic ** foot**; and the

**2.0**ton

*golden*sphere, with the

**1.0 m**surface area, encompasses (.

^{2}**0940**…) of a cubic

**.**

*meter***.388841339… / 20 = .0194420670… **

** ****.0194420670… X 1.0 cu. ft. = 33.59589… cu. in.**

** ****1.0 pint dry = 33.60031250… cu. in.**

** ** The *troy* *ounce* is solidly represented in the various ways of expressing this tetrahedron’s unique *volume*. First as was mentioned earlier, this volume in pure gold weighs **8500** *troy* *ounces* and is the weight needed to “complete” the **3.0**-ton cuboid made with **27** *mg*. cubets. And its’ *volume*, this time expressed in *gallons* *dry*, is **3.110**64… and of course this is a power of the **31.10**34… *grams* in a *troy* *ounce*. Now a *gallon* *dry*, being half a *peck*, makes this tetrahedron’s volume **1.5553**3… *peck*, and this quantity is also the *weight* of one *pence* in *grams* (a *pence* being **1/20**^{th} a *troy* *ounce*). When this *volume* is further broken down into smaller dry measure increments it is found to be the equivalent of **12.44**2703… *quarts* *dry*; or, **24.88**5633… *pints* *dry*. Between 1853 and 1873 these were the weights *in grams* of America’s fractional silver dollar (**24.88**2781…) and half-dollar (**12.44**1390…).

It is essential that the reader understand the following: the *geometry* explaining the *surface* and *volume* transformations has nothing to do with any specific *weight*. The *weight* applies to the “named” substance occupying the *volume* and will vary in a direct relationship to its *density*. Consequently, of all the natural elements GOLD is the ONLY one that can be modeled in *commensurate* “human” measures in the forms illustrated above. I ask the reader, *how can all of this be attributed in any way to “coincidence”?*

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